PHYSICS HIGH SCHOOL

What is the value of x in the equation below 1+2e^x+1=9

Answers

Answer 1

Answer:

Answer: 1.252

Explanation:

We are given this equation and we need to find the value of $x$ :

$1+2e^x+1=9$ (1)

Firstly, we have to clear $x$ :

$2e^x=9-1-1$

$2e^x=7$

$e^x=(7)/(2)$ (2)

Applying Natural Logarithm on both sides of the equation (2):

$ln(e^x)=ln((7)/(2))$ (3)

$xln(e)=ln((7)/(2))$ (4)

According to the Natural Logarithm rules $xln(e)=x$ , so (4) can be written as:

$x=ln((7)/(2))$ (5)

Finally:

$x=1.252$

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Answers

The material in which a wave travels is called a medium. Hope this helps!

Hey there the answer is medium

Astronauts in orbit are not truly weightless. Please select the best answer from the choices provided T F

Answers

That's true. There's plenty of gravity in Earth orbit, and things have plenty of weight there.

Answer:

true

Explanation:

true

What is absolute zero

Answers

An absolute zero is when all forms of being cease to move due to low to none existing thermal energy between all living things. It follows the statement of Kelvin’s temperature scale where the temperature is -275.15K or -546.3°C.

What is the product of nuclear fission?a. two different atoms that are isotopes of the original atom
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d. two different atoms that have the same number of neutrons as the original atom User: What is released when the nuclei of two smaller atoms fuse to form a larger atom?
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Answers

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The net charge of 3 mol of protons isa) 4.81×10 4 C .
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c) 4.81×10 −19 C
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Answers

The charge of 1 mole of proton is equivalent to 1.60217656x10^-19 coulombs. This is also called an elementary charge. Multiply that by 3 to get the net charge of three moles of protons.

Charge of 3 mol protons = 3 x 1.60217656x10^-19 = 4.81x10^-19 coloumbs

So the answer is c) 4.81×10 −19 C

5. Projectile A with mass m is launched at an angle of 20° above the horizontal with a speed v0. Projectile B also with mass m is launched from the same location at an angle of 70° above the horizontal, also with speed v0. Thus, both projectiles have the same initial total energy. a. Which projectile has a larger speed when it hits the ground or do they have the same speed? Explain using energy. b. Which projectile reaches a greater height? Given that both projectiles have the same initial energy, how is this possible?

Answers

Answer:

a) They both have the same final speed.

b) Projectile B reaches a greater height

Explanation:

The initial total energy of both projectiles is the same, and since the initial height is zero, that initial energy is entirely kinetic energy:

$E_0=K_0=(1)/(2)mv_0^(2)$

Now, when the projectiles are going to reach the ground, their height also becomes zero, so the final energy is also entirely kinetic energy:

$E_f=K_f=(1)/(2)mv_f^(2)$

As stated in the conservation of mechanical energy, the final total energy has to be equal to the initial total energy, and then:

$E_0=E_f\n \n (1)/(2)mv_0^(2)=(1)/(2)mv_f^(2)\n\n\implies v_0=v_f$

Finally, since the initial speed is the same for both projectiles, they have the same speed when they hit the ground (a).

Next, we know that the height reached by a projectile depends only of their initial vertical velocity, nor their horizontal one. So, the projectile with the highest initial vertical velocity has to reach a greater height. We use trigonometry to calculate that:

$v_0_A_y=v_0\sin20\°=0.34v_0\n\nv_0_B_y=v_0\sin70\°=0.93v_0$

It means that projectile B has a higher initial vertical velocity, so it reaches a greater height (b).

This is possible because some of the kinetic energy of both projectiles is never transformed to gravitational potential energy (because is related to the horizontal velocity) and this amount of kinetic energy depends on the angle at which the projectile is launched. As their potential energies at the highest points are different, their maximum heights are, too.

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