The volume is (area of cross-section) x (length) .
-- The cross-section is a triangle. The area of a triangle is
Area = (1/2) (base) (height) .
In this one, the base is 9/4 m and the height is 3-1/3 m .
Area = (1/2) (9/4 m) (3-1/3 m)
Area = (1/2) (9/4) (10/3)
Area = 90/24 m² .
-- Volume = (area of cross-section) x (length)
Volume = (90/24 m²) x (7-1/3 m)
Volume = (90/24) x (22/3) m³
Volume = (1,980 / 72) m³
Volume = 27.5 m³
Answer: The value of x = 5.
Step-by-step explanation:
Given linear equation is 12-x=7 with variable x
To find the solution i.e. the value of x of the given linear equation, we need to perform following steps:
Step 1. Subtracting 12 from the both sides of the equation,we get
⇒12-x-12=7-12
⇒-x=-5
Step 2. Multiplying (-1) on the both sides ,we get
⇒-x × -1=-5 × -1
⇒x=5
So ,the value of x=5
Thus required solution of the given linear equation is x=5.
12-x=7. Well if you look at seven you should Be able to subtract 7 from 12 and get five.
You x Value = 5!
b) 32 notes in 4 measures, 12 notes in 2 measures
Show work if you can please :)
The rates 28 points in 3 games and 112 points in 12 games form a proportion, while the rates 32 notes in 4 measures and 12 notes in 2 measures do not form a proportion.
To determine whether the given rates form a proportion, we need to check if the ratios are equivalent. a) We'll start with 28 points in 3 games vs 112 points in 12 games. The ratio 28/3 equals approximately 9.33, and the ratio 112/12 also equals approximately 9.33. Since these ratios are equal, these rates do form a proportion. b) Moving to 32 notes in 4 measures vs 12 notes in 2 measures. The ratio 32/4 equals 8, and the ratio 12/2 equals 6. Since these ratios are not equal, these rates do not form a proportion.
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the ball will take 6.5 seconds to hit the ground
The question from the student is about time airborne for a volleyball hit upwards with an initial velocity. A physics equation of motion is utilized to solve it by inserting the values and extracting time.
The subject of the question is physics, specifically the subtopic of kinematics in terms of upward motion. The problem can be solved by using the equation of motion: `y = y0 + v0 * t - 0.5 * g * t²`, where y0 is the initial height, v0 is initial velocity, g is the acceleration due to gravity and t is the time taken. In this situation:
Set y (the final position) to 0 (ground level), and solve for t (time taken):
0 = 1m + (13 m/s) * t - 0.5 * (9.8 m/s²) * t²
Solving this quadratic equation, we get two solutions as the time cannot be negative for this context, so choose the positive value as the time taken for the ball to hit the ground. This will give the duration the volleyball remains in the air after being hit by Martina.
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