If a price is 60$ and it gets a 15% markup,what would the final price be?

Answers

Answer 1
Answer: Simple,

to find the rate of selling price price based on cost....-rate of cost+rate of the markup..

In work..

S%=C%+M%

The cost is $60 and C is 100%, also you know M%=15%

S%=100%+15%=115%

Rate of the selling price=115%

Step 2: Find the selling price

S=S%*CS=115%*$60S=1.15*60=$69

The selling price at a 15% markup is $69.

Thus, your answer.
Answer 2
Answer: Well, set up a proportion first.
x/60 = 15/100
solve the proportion to get the amount of money it was marked up: $9.
Add 9 to 60,
The final price would be $69.

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90% as a decimal rounded to the thousands place

Answers

90\%= (9)/(10) = .9 \n\boxed{.9}
You can't round it to the thousandths place.
I think it's hits 9/10

Please help!

I dont understand this

Answers


You must have learned "Order of Operations" or PEMDAS by now,
because that's what this whole question is talking about.  

Look at the one in the first box:

                  32 ÷ 4² + 35 - 20 ÷ 5

You know how to do 4², and you know how to do 20÷5, and you know
how to do 4²+35, and you know how to do 35-20 .

But which one should you do first ? ! ?

pEmdas . . . do exponents.  4² = 16

Now you have    32÷16 + 35 - 20÷5

pemDas . . . do division.      32÷16 = 2

                                   and    20÷5 = 4

Now you have      2  +  35  -  4

pemdAs . . . do addition:  2 + 35 = 37

Now you have        37 - 4

pendaS . . . Do subtraction:      37 - 4  =  33

That's the whole ugly thing in the first box.  It's 33 .

Do the other two boxes the same way.  Then you'll have a single number
for each box.  Then just line up the three numbers in the order of their size.

This is all just one big PEMDAS exercise.  If you do the operations in the
wrong order in one of the boxes, then you'll get the wrong number in that box.

What is the largest positive integer value of m such that the equation 3x^2 - mx + 7 = 0 has no real solutions?

Answers

use determinant
in form ax²+bx+c=0
when b²-4ac>0, it has 2 real roots
when b²-4ac=0, it has 1 real root
when b²-4ac<0, it has no real roots
so


we solve for no real roots
b²-4ac<0
a=3
c=7
b=-m

(-m)²-(4)(3)(7)<0
m²-84<0
add 84 both sides
m²<84
sqrt both sides
m<9.1 about
nearest integer
round down
m=9

answer is m=9

At the market, 2.4 pounds of carrots cst 1.68$ and 1.8 pounds of broccoli cost 1.53$ how much more does1 pound of broccoli cost than 1 pound of carrots

Answers

Answer:

0.15 cents

Step-by-step explanation:

see 1 pound of brocolie is 0.85 and 1 pound of carrosts cost 0.70. so 0.85 - 0.70 = 0.15

A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 60 pounds each, and the small boxes weigh 20 pounds each. There are 125 boxes in all. If the truck is carrying a total of 4700 pounds in boxes, how many of each type of box is it carrying?

Answers

Answer:

55 large boxes and 70 small boxes

Step-by-step explanation:

We understand that there are two unknowns in this problem: the number of large boxes and the number of small boxes.

Let's identify with the letter L the number of large boxes that are transported, and with the letter S the number of small boxes, so we can easily identify the unknowns when writing and reading our equations and final answers.

Set up two equations:

1) one for the total weight of the boxes being transported (which should add up to 4700 pounds), and considering that we have "L" number of large boxes (each one 60 pound weight), and "S" number of boxes (each one 20 pound weight):

60 * L + 20 * S = 4700

2) another equation for the total number of boxes (125) which should be addition of L large boxes and S small ones:

L + S = 125

Now solve for one of the unknowns (let's say for example "S") in the easy second equation we wrote:

S = 125 - L

Now use this expression for "S" (to replace it in terms of L) in the first (more complex) equation:

60 * L + 20 * (125-L) = 4700

Now apply distributive property to remove the parenthesis on the second term on the left of the equation:

60 * L + 2500 - 20 * L = 4700

subtract 2500 from both sides (to group all numerical terms on the right hand side):

60 * L - 20 * L = 4700-2500= 2200

combine the like terms 60L and -20L:

40 * L = 2200

now divide both sides by 40 to solve for L

therefore: L = 2200 / 40 = 55

There are 55 large boxes.

Now to find the number of small boxes, we use this result: "L=55" in the second (simple/easy) equation we created:

S = 125 - L = 70

Therefore, there are 70 small boxes.

What expression represents the sum of (2x-5y) and (x+y)

Answers

Equation: (2x-5y) + (x+y)
Add x terms together: 2x + x=3x
Add y terms together: -5y + y=-4y
Simplify: 3x-4y

Final Answer: 3x-4y