A school band sold 30 raffle tickets, each labeled with a number from 1 to 30. One winning ticket will be drawn.What is the probability that the number of the winning ticket will be a multiple of 4 or the number 19? Express your answer in simplest form.

Answers

Answer 1

Answer: The Correct answer is 4/15 I took the same quiz I got it right.

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in local theaters showing an animated movie they charge $5 per ticket for a child and $12 per ticket for an adult they sell a total of 342 tickets and make a total of $2,550 we want to try to find out how many of each type of ticket they so let C represent the number of children tickets sold and A represent the number of adult tickets to write an equation that represents the fact that 342 tickets were sold also write an equation representing the fact that they made it to a total of 2550 also solve the system you created in A & B by the method of elimination

Answers

Answer: C=222 and A =120

Step-by-step explanation:

Let C be the number of children tickets and A be the number of adult tickets.

Then, According to the question, we have the following system:-

$C+A=342........................(1)\n5C+12A=2550........................(2)$

Multiply equation (1) by 5 on both sides ,we get

$5C+5A=1710..........(3)$

Eliminate equation (3) from equation (2), we get

$7A=840\n\Rightarrow\ A=120$

Substitute the value of A in (1), we get

$C+120=342\n\Rightarrow\ C=222$

Hence, the number of children tickets sold = 222 and the number of adult tickets sold =120

C+A=342
$5C+$12A=$2,550

5C+5A=1710
5C+12A=2550
-7C=-840
C=120

5(120)+12A=2550
600+12A=2550
12A=1950
A=163

18 divided by x = -2 what is the x equal to?

Answers

18/x=-2
isolate x by multiply both sides by x:
18=-2x
divide by -2
-9=x

Suppose you just received a shipment of twelve televisions. Three of them are defective. Assuming that two televisions are randomly selected, find the following probabilities:What is the probability that both televisons work?
What is the probability that at least one does not work?

Answers

The probability that both televisons work is 18/33.
The probability that at least one does not work is 15/33.

Let x = number of shipments, x = 12
P(defective) = 3/12
P(working) = 9/12
The probability that two randomly selected televisions are both working is:
9/12 * 8/11 = 72 / 132 or 18/33
P(2 working) = 18/33
8/11 is used for the second selection since the number of televisions has been reduced due to the first selection.

The probability of 1 not working among the two can be solved through"
P(at least one defective among the 2) = 1 - P(2 working)
P(at least one defective among the 2) = 15/ 33

Thank you for posting your question. I hope you found you were after. Please feel free to ask me another.

Answer:

Step-by-step explanation:

Find the area, please

I’ll give brainlist

Answers

Answer:

Area = 104 m²

Step-by-step explanation:

the figure is composed of a rectangle and a triangle

area of rectangle = length × breadth = 10 × 8 = 80 m²

area of triangle = $(1)/(2)$ × base × perpendicular height

the base of the triangle is opposite the 8 m side of the rectangle and is 8 m

the perpendicular height of the triangle is 6m , then

area of triangle = $(1)/(2)$ × 8 × 6 = 4 × 6 = 24 m²

sum the areas of the two parts

area = 80 + 24 = 104 m²

Help on a question geometry

Answers

2log 3 = log 3^2 = log 9 ;
log 5 + 2log 3 = log 5 + log 9 = log( 5 * 9 ) = log 45 ;
log ( x - 12 ) = log 45;
x - 12 = 45 ;
x = 12 + 45 ;
x = 57 ;
But, x - 12 > 0;
And, 57 - 12 > 0 ;
The solution is 57 .

$D:x-12>0\nD:x>12\n\log_3(x-12)=\log_35+2\log_33\n\log_3(x-12)=\log_35+\log_33^2\n\log_3(x-12)=\log_35+\log_39\n\log_3(x-12)=\log_3(9\cdot5)\n\log_3(x-12)=\log_345\nx-12=45\n\boxed{x=57}$

The formula for the area of a trapezoid is A=1/2h(b1+b2) express b1 in terms of A, h and b2

Answers

The expression of b1 in terms of A, h, and b2 is expressed as $b_1 =(2A)/(h) - b_2$

Given the formula for calculating the area of a trapezoid expressed as:

$A = (1)/(2)h(b_1+b_2)$

We are to express b1 in terms of A, h, and b2 as shown

$A = (1)/(2)h(b_1+b_2)\n2A = h(b_1+b_2)\n(2A)/(h) = b_1 + b_2\n b_1 =(2A)/(h) - b_2$

Hence the expression of b1 in terms of A, h, and b2 is expressed as $b_1 =(2A)/(h) - b_2$

Learn more here: brainly.com/question/21406377

the answer is b1=(2A/h)-b2

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