Tom,Scott and dawn sold cookies at the school fair.Tom had 90 cookies and sold 60% of them.
Scott had 150 cookies and sold 2/3 of them.
Dawn sold 46 cookies.
What percentage of the cookies sold were sold by Dawn?

Answers

Answer 1

Answer: first of all work out how many tom and scott sold.
tom sold 60% of 90 cookies which is 54.
scott sold 2/3 of 150 cookies which is 100.
altogether the three of them sold 54+100+46 cookies which is 200.
Dawn sold 46 of these 200 cookies. To work out the percentage we have both the numbers to get 23 out of 100. We halved those numbers because a percentage is out of 100 we halved it to get it out of 100.
so 23 out of 100 is 23% so dawn sold 23%of the cookies.

Hope this helps :)

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Explain how an expression becomes a equation?

Answers

An expression becomes an equation by adding an equal sign to the end of the expression and if there's a number on the other side of the equation. For example, 4+3 becomes an equation if you put 4+3=7. Or, 4+3=2+5. Good luck!

cyclist were 3/4 finished with their ride when they reached the 15 kilometer mark. how long was the ride?

Answers

20km

15km 3/4
_____ = ___
Xkm 4/4

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Monte performs an experiment using 2 identical graduated cylinders with a radius of 2 cm. The volume of the liquid in the first graduated cylinder is 188.4 cm3. The volume of the liquid in the second graduated cylinder is 314 cm3.What is the difference in the height of the liquid in the two cylinders?

Use 3.14 to approximate pi.

Answers

Answer:

The difference of height is 10 cm

Step-by-step explanation:

Monte performs an experiment using 2 identical graduated cylinders with a radius of 2 cm.

The volume of the liquid in the first graduated cylinder is 188.4 cm³

The volume of the liquid in the second graduated cylinder is 314 cm³

Let height of first graduated cylinder be h₁ and radius (r) = 2 cm

Let height of second graduated cylinder be h₂ and radius (r) = 2 cm

Formula:

$\text{Volume of cylinder}=\pi r^2h$

$\text{Volume of 1st cylinder}=\pi\cdot 2^2h_1$

$188.4=3.14\cdot 2^2\cdot h_1$

$h_1=15$ cm

$\text{Volume of 2nd cylinder}=\pi\cdot 2^2h_2$

$314=3.14\cdot 2^2\cdot h_2$

$h_2=25$ cm

The difference in the height of the liquid in two cylinder,

$\Rightarrow h_2-h_1$

$\Rightarrow 25-15$

$\Rightarrow 10$ cm

Hence, The difference of height is 10 cm

Volume of a cylinder of radius r, height h : $V=\pi*r^2*h$

hence the height of the liquid in the first cylinder is $h1=(188.4)/(2^2\pi)=15$ cm, and in the second cylinder $h2=(314)/(2^2\pi)=25$ cm

Hence the difference is h2-h1=25-15=10 cm

What is the product?(-35+21)(45-1)
0 -1252-2??
0 -1252 +2e?
0 -1252 +8st – 202
0 -12s2+11st – 2x2

Answers

Answer:

-616

Step-by-step explanation:

None of these answers are correct... maybe you entered the equation in wrong. There are no variables so answers B,C, and D would be incorrect. And A is incorrect as well. Again, check the equation... may be wrong.

Factor the polynomial expression x6 – x3 – 20

Answers

Answer:

x6 − x3 − 20 = (x3)2 − x3 − 20 = (x3 + 4)(x3 − 5)

Step-by-step explanation:

In this trinomial, the exponent of the first term, 6, is double the exponent in the second term, 3. And, the third term contains no variables. So, we can factor the expression as we would a quadratic, but treating x3 as if it were x:

Answer:

(x³ - 5)(x³ + 4)

Step-by-step explanation:

Consider the factors of the constant term (- 20) which sum to give the coefficient of the x³ term (- 1)

The factors are - 5 and + 4, since

- 5 × 4 = - 20 and - 5 + 4 = - 1, hence

$x^(6)$ - x³ - 20 = (x³ - 5)(x³ + 4)