A movie theater offers popcorn in two different containers for the same price. One container is a trapezoidal prism with a base area of 34 square inches and a height of 5 inches. The other container is a triangular prism with a base area of 35 square inches and a height of 6 inches. Complete the explanation on which is a better deal:The (_trapezoidal or triangular__) prism is a better deal because you get ______ inches cubed for the same price you would pay for _______ inches cubed with a (_trapezoidal or triangular_) prism.
Answers
Given: Trapezoidal prism: base area = 34 in² ; height = 5 in Triangular prism: base area = 35 in² ; height = 6 in
Volume of Trapezoidal prism = base area * height V = 34 in² x 5 in V = 170 in³
Volume of Triangular prism = base area * height V = 35 in² x 6 in V = 210 in³
The TRIANGULAR prism is a better deal because you get 210 inches cubed for the same price you would pay for 170 inches cubed with a TRAPEZOIDAL prism.
Answer:
triangular
Step-by-step explanation:
At a pie eating contest, Jonny ate 8 pies in 5 minutes. How much time did he spend on each pie?
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Five minutes is 120 seconds. If you divide 120/8 to get seconds per pie, then your answer is: 15 seconds per pie.
The number 6 is halfway between 2.8 and...? the number 6 is halfway between -12 and...?
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if 6 is halfway between 2.8 and x, then the distance from 2.8 to 6 is 1/2 the distance from 2.8 to something find the distance
6-2.8=3.2 1/2 distance=3.2 multiply by 2 to find whole distance 3.2 times 2=6.4 add 2.8+whole distance=2.8+6.4=9.2
6 is halfway between 2.8 and 9.2
6 is halfwa between -12 and something find distance 6-(-12)=6+12=18 1/2 distance=18 times 2 18*2=36 add -12+36=24
6 is halfway between -12 and 24
blanks are 6 is halfway betwen 2.8 and 9.2 6 is halfway betwen -12 and 24
Please help! I’m stuck
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I thick it is 6c...because I need to help someone
Add three data values to the following data set so the mean increases by 10 and the median does not change. {42, 37, 32, 29, 20}
Answers
Sum of the numbers in the set: 42+37+32+29+20 =160
Current mean: 160/5 = 32
Median = the valvue of the middle = 32.
New mean: 32+10= 42.
Sum of numbers in the new set = 42*8 = 336
Difference: 336 - 160 = 176
I want to include 32, so that the new median stays in 32.
So the other two numbers must add 176 - 32 = 144
I will use a smaller number than 32 and the other greater (again in order to keep the same median.
I will choose 28 and 144 - 28 = 116.
So my three new numbers are 28, 32 and 116 and the new set is {116, 42, 37, 32, 32, 29,28, 20}
Checking:
Sum of the terms: 116+42+37+32+32+29+28+20 = 336
Mean = 336 / 8 = 42, which is 10 more than the original mean.
And the new median is (32+32)/2 = 32. The same of the original set.