****BRAINLIEST The graph shows the solution for which inequalities?y ≥ x + 2 and y ≤ 2x + 3
y ≥ x - 2 and y ≤ 2x - 3
y ≥ 3x - 2 and y ≤ x + 3
y ≤ 3x - 2 and y ≥ x + 3

Answers

Answer 1

Answer:

The graph shows the solution for the inequalities y ≥ 3x - 2 and y ≤ x + 3.

How can find the inequalities?

The inequalities can be found by substituting the coordinates of a point within the shaded area in both inequalities and seeing if they are satisfied.

We can find the inequalioties as follows:

The options are given.

Let us take the options one by one:

Option A: y ≥ x + 2 and y ≤ 2x + 3

Now, substitute (0,0) in the inequalities:

0 ≥ 2 and 0 ≤ 3

This is not true.

Option B: y ≥ x - 2 and y ≤ 2x - 3

Now, substitute (0,0) in the inequalities:

0 ≥ - 2 and 0 ≤ - 3

This is not true.

Option C: y ≥ 3x - 2 and y ≤ x + 3

Now, substitute (0,0) in the inequalities:

0 ≥ - 2 and 0 ≤ 3

This is true.

Option D: 0 ≤ - 2 and 0 ≥ 3

Now, substitute (0,0) in the inequalities:

0 ≥ - 2 and 0 ≤ - 3

This is not true.

Therefore, we have found that the inequalities are y ≥ 3x - 2 and y ≤ x + 3. The correct answer is option C.

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Answer 2

Answer:

Answer:

$y\geq 3x-2$ and $y\leq (1)/(2) x+3$

Step-by-step explanation:

Blue:

The inequality for the blue line is

$y\geq 3x-2$

Yellow

The inequality for the yellow line is

$y\leq (1)/(2) x+3$

This means that the correct answer is the third option,

$y\geq 3x-2$ and $y\leq (1)/(2) x+3$

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Cierra has 3 more than one half as many purses as Aisha. Define a variable and write an expression to represent the number of purses in Cierra's collection. Then find the number of purses in Cierra's collection if Aisha has 12 purses.

Answers

Here is the answer.

x = number of Cierra's purses

y = number of Aisha's purses

Equation =

y/2 + 3 = x

12/2 + 3 = x

6 + 3 = 9

Cierra has 9 purses

Work out the size of angle x

Answers

The size of angle x is 99 degree

What is straight angle and Exterior angle theorem?

The exterior angle theorem states that the measure of an exterior angle is equal to the sum of the measures of the two remote interior angles of the triangle. straight angle: an angle whose sides lie in opposite directions from the vertex in the same straight line and which equals two right angles.

We have,

∠CDE = $123^(o)$

∠BCD = $42^(o)$

∠ABC = $x^(o)$

According to the question

Angle Addition Postulate and definition of straight angle:

∠BDC+∠CDE = $180^(O)$

Substitute into : ∠BDC + $123^(o)$ = $180^(o)$ ∠BDC = $180^(o)$ - $123^(o)$ ∠BDC = $57^(o)$

Exterior Angle Theorem:

∠BDC + ∠BCD = ∠ABC

Substitute into :

$57^(o)$ + $42^(o)$

= $x^(o)$ $x^(o)$

= $99^(o)$

hence, the size of angle x is 99 degree

Learn more about exterior angle theorem from here

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Answer:

Step-by-step explanation:

42+123=165

165+50=215

215+145=360

F(x)= squareroot of x between x=1 and x=9

Answers

Answer:

Step-by-step explanation:

hello :

F(x)= squareroot(x)

x=1 : F(1)= squareroot(1) = 1

x=9 : F(9)= squareroot(9) = 3

the measure of the angles of a triangle are represented by (2x)°, (x+40)°, and (x)°. what is the measure of the largest angle of the triangle?

Answers

Sum of angles of a triangle : 180°

So, 2x + x + 40 + x = 180

4x + 40 = 180
4x = 180 - 40
4x = 140
x = 35°

So, angles -
x = 35°
2x = 2×35° = 70°
x + 40 = 35°+40° = 75°

So, largest angle - 75°

Help how to solve! 24=3r divided by 4

Answers

24=3r/4
multiply 4 on both sides
96=3r
divide 3r and 96 by 3
r=32

Conrad has a collection of three types of coins: nickels,dimes,and quarters.There are five more nickels than quarters but four times as many dimes as quarters.If the entire collection is worth $5.85,how many nickels,dimes,and quarters are there?

Answers

n=number of nickles
d=number of dimes
q=number of quarters
use cents for everything

total value=585
5n+10d+25q=585
divide everybody by 5 to simplify
n+2d+5q=117

we have

nicles are 5 more than quarters
n=5+q

4 times as many dimes as quarters
d=4 times q
d=4q

sub those in
5+q+2(4q)+5q=117
5+6q+8q=117
5+14q=117
minus 5
14q=112
q=8

sub back
n=5+q
n=5+8
n=13

d=4q
d=4(8)
d=32

13 nickles
32 dimes
8 quarters
divide both sides by 22

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