X^2-6x-25=0. Solve by completing the square.
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x^2 -6x+25=0
Per quadratic formula, roots of ax^2+bx+c are
x=[-b+sqrt(b^2-4ac)]/2a and x=[-b-sqrt(b^2-4ac)]/2a
In this example, a=1, b=-6, and c=25
So, x= [6+sqrt(36-100)]/2 and x= [6-sqrt(36-100)]/2
=> x = [6+sqrt(-64)]/2 and x = [6-sqrt(-64)]/2
=> x = 3+4i and x= 3-4i
Hope this helped you alot!!!!!!!!
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Exact Form:
917
Decimal Form:0.52941176…
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Answer:
3. Option D
5. Option B
13. Option D
17. Option B
Step-by-step explanation:
Question 3
4C means that, multiply 4 with all the terms in the matrix A . We get option D.
Question 5
Matrix A + matrix B means that add corresponding terms of each matrix.
We get option B.
Question 13
Here we have to find a₁,₂ (the term in which first row second column)
a₁,₂ = 2
We get option D.
Question 17
B - CF - First multiply matrix C with matrix F and subtract it from Matrix B.
We get option B
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The sequence was following the pattern of squaring numbers that were in chronological order.
1^2=1
2^2=4
3^2=9
4^2=16
So, next number would be 5^2=25.
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Answer:
Step-by-step explanation:
It has kinetic energy and potential energy
It has some kinetic energy
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ba = b +cd
a = b+cd/b