Which of the following is not a dwarf planet?A. Hydra
B. Haumea
C. Eris
D. Pluto

Answers

Answer 1
Answer: The correct answer is (a.) Hydra. Hydra is not a dwarf planet, instead, it is the moon of the dwarf planet, Pluto. There are only four accepted dwarf planets by the International Astronomical Union which were the Haumea, Pluto, Eris, and Makemake. 
Answer 2
Answer:

The planet that is considered or classified as a dwarf planet include the following: A. Hydra.

What is a planet?

A planet is a terminology which is used to describe a large astronomical (celestial) body that has sufficient mass to allow for self-gravity and make it assume a nearly circular shape or spherical shape.

Based on astronomical records, there are nine (9) planets in the solar system and these include the following;

  1. Mercury
  2. Venus
  3. Earth
  4. Mars
  5. Jupiter
  6. Saturn
  7. Uranus
  8. Neptune
  9. Pluto

In conclusion, we can reasonably infer and logically deduce that Hydra cannot be considered or classified as a dwarf planet because it is typically the moon of the dwarf planet, referred to as Pluto.

Read more on planet here: brainly.com/question/11172693

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An object with mass 60 kg moved in outer space. When it was at location < 13, -19, -3 > its speed was 3.5 m/s. A single constant force < 220, 320, -120 > N acted on the object while the object moved from location < 13, -19, -3 > m to location < 18, -11, -8 > m. Then a different single constant force < 150, 230, 220 > N acted on the object while the object moved from location < 18, -11, -8 > m to location < 22, -17, -3 > m. What is the speed of the object at this final location?final speed = m/s

Answers

The speed of the object at its' final location is; 38 m/s

What is work energy theorem?

For the first force, we are given;

Force; F₁ = 220i + 320j - 120k

Initial Position; r₁ = 13i - 19j - 3k

Final Position; r₂ = 18i - 11j - 8k

Thus; Displacement; Δr = r₂ - r₁

Δr = 18i - 11j - 8k - (13i - 19j - 3k)

Δr = 5i + 8j - 5k

From work energy theorem, we know that;

F₁ * Δr = ¹/₂m(v₂² - v₁²)

We are given v₁ = 2.5 m/s and m = 60 kg. Thus;

(220i + 320j - 120k) × (5i + 8j - 5k) = ¹/₂ * 60(v₂² - 3.5²)

4260/30 = v₂² - 3.5²

1420 = v₂² - 12.25

Solving gives v₂ = 37.85 m/s

For the second force, we are given;

Force; F₂ = 150i + 230j - 220k

Initial Position; r₁ = 18i - 11j - 8k

Final Position; r₂ = 22i - 17j - 3k

Thus; Displacement; Δr = r₂ - r₁

Δr = 22i - 17j - 3k - (18i - 11j - 8k)

Δr = 4i - 6j + 5k

From work energy theorem, we know that;

F₂ * Δr = ¹/₂m(v₂² - v₁²)

Now,  v₁ = 37.85 m/s and m = 60 kg. Thus;

(150i + 230j + 220k) × (4i - 6j + 5k) = ¹/₂ * 60(v₂² - 37.85²)

320/30 = v₂² - 37.85²

10.67 = v₂² - 1,432.6225

Solving gives v₂ = 38 m/s

Read more about Work Energy theorem at; brainly.com/question/14468674

Sigma F.dS = total work done = change in kinetic energy
(220, 320, -120).(18-13,-11+19,-8+3) +(150, 230, 220).(22-18,-17+11,-3+8)= 1/2 *60*(V^2- 3.5^2)

220*5+320*8+ -120*-5 + 150*4 + 230* 6 +220* -5= ..
simplify his

A constant net torque is applied to a rotating object. Which of the following best describes the object's motion?a. The object will rotate with increasing angular acceleration.
b. The object will have a decreasing moment of inertia.
c. The object will rotate with constant angular velocity.
d. The object will have an increasing moment of inertia.
e. The object will rotate with decreasing angular acceleration.
f. The object will rotate with constant angular acceleration.

Answers

Answer:

f. The object will rotate with constant angular acceleration.

Explanation:

We know that

τ = I α

τ=Torque

I=Moment of inertia of the object

α =Angular acceleration

The moment of inertia is constant for an object and it does not depends on the applied torque.

If applied torque is constant then the angular acceleration of the object will be constant because moment of inertia is constant.

If angular speed is constant then the angular acceleration will,be zero.But in this case object is having angular acceleration that is why it have varying angular speed.

Therefore option "f" is correct.

T or f Halogens are the basis of all fossil fuels.

Answers

The statement about “Halogens are the basis of all fossil fuels.” is false. It is the carbon that is the basis of all fossil fuels. 

A system uses 2,380 J of energy to do work as 12,900 J of heat are added to the system. What is the change in internal energy of the system?

Answers

The internal energy of the system is characterized by the equation U = Q + W where U is the internal energy, Q is the heat and W is work. You are given 2,380 J of energy to do work as 12,900 J of heat so add up. The internal energy is 15,280J.

Explanation:

The relation between change in internal energy, work and heat is as follows.

                    Q = \Delta U + W

where,       Q = heat absorbed or released by the system

                \Delta U = change in internal energy

                W = work done by or on the system

It is given that system uses 2,380 J of energy to do work. This means that work is done by the system therefore, the value of work done by the system is negative. Heat added to the system is 12,900 J.

Therefore, calculate change in internal energy as follows.

                       \Delta U = Q - W

                               = 12,900 J - (-2,380 J)

                               = (12,900 + 2,380) J

                               = 15,280 J

Thus, we can conclude that the change in internal energy of the system is 15,280 J.

       

a graph depicts force versus position. what represents the work done by the force over the given displacement?

Answers

The area under the graph. W = f d cos(theta), so you want the number that is force times displacement, which corresponds to the area under the graph.

Terminal velocity and Inicial velocity they are related???

Answers

Well the only relation they have is that they are both velocities.

The initial velocity of an object is the velocity it begins moving with. i. e if a ball is thrown its initial velocity is the velocity it has once it leaves the hand.

Terminal velocity is the maximum velocity an object can achieve when it is in free fall. i.e if a bowling ball is dropped from a plane, its velocity will increase until it reaches terminal velocity.