The planet that is considered or classified as a dwarf planet include the following: A. Hydra.
A planet is a terminology which is used to describe a large astronomical (celestial) body that has sufficient mass to allow for self-gravity and make it assume a nearly circular shape or spherical shape.
Based on astronomical records, there are nine (9) planets in the solar system and these include the following;
In conclusion, we can reasonably infer and logically deduce that Hydra cannot be considered or classified as a dwarf planet because it is typically the moon of the dwarf planet, referred to as Pluto.
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The speed of the object at its' final location is; 38 m/s
For the first force, we are given;
Force; F₁ = 220i + 320j - 120k
Initial Position; r₁ = 13i - 19j - 3k
Final Position; r₂ = 18i - 11j - 8k
Thus; Displacement; Δr = r₂ - r₁
Δr = 18i - 11j - 8k - (13i - 19j - 3k)
Δr = 5i + 8j - 5k
From work energy theorem, we know that;
F₁ * Δr = ¹/₂m(v₂² - v₁²)
We are given v₁ = 2.5 m/s and m = 60 kg. Thus;
(220i + 320j - 120k) × (5i + 8j - 5k) = ¹/₂ * 60(v₂² - 3.5²)
4260/30 = v₂² - 3.5²
1420 = v₂² - 12.25
Solving gives v₂ = 37.85 m/s
For the second force, we are given;
Force; F₂ = 150i + 230j - 220k
Initial Position; r₁ = 18i - 11j - 8k
Final Position; r₂ = 22i - 17j - 3k
Thus; Displacement; Δr = r₂ - r₁
Δr = 22i - 17j - 3k - (18i - 11j - 8k)
Δr = 4i - 6j + 5k
From work energy theorem, we know that;
F₂ * Δr = ¹/₂m(v₂² - v₁²)
Now, v₁ = 37.85 m/s and m = 60 kg. Thus;
(150i + 230j + 220k) × (4i - 6j + 5k) = ¹/₂ * 60(v₂² - 37.85²)
320/30 = v₂² - 37.85²
10.67 = v₂² - 1,432.6225
Solving gives v₂ = 38 m/s
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b. The object will have a decreasing moment of inertia.
c. The object will rotate with constant angular velocity.
d. The object will have an increasing moment of inertia.
e. The object will rotate with decreasing angular acceleration.
f. The object will rotate with constant angular acceleration.
Answer:
f. The object will rotate with constant angular acceleration.
Explanation:
We know that
τ = I α
τ=Torque
I=Moment of inertia of the object
α =Angular acceleration
The moment of inertia is constant for an object and it does not depends on the applied torque.
If applied torque is constant then the angular acceleration of the object will be constant because moment of inertia is constant.
If angular speed is constant then the angular acceleration will,be zero.But in this case object is having angular acceleration that is why it have varying angular speed.
Therefore option "f" is correct.
The internal energy of the system is characterized by the equation U = Q + W where U is the internal energy, Q is the heat and W is work. You are given 2,380 J of energy to do work as 12,900 J of heat so add up. The internal energy is 15,280J.
Explanation:
The relation between change in internal energy, work and heat is as follows.
where, Q = heat absorbed or released by the system
= change in internal energy
W = work done by or on the system
It is given that system uses 2,380 J of energy to do work. This means that work is done by the system therefore, the value of work done by the system is negative. Heat added to the system is 12,900 J.
Therefore, calculate change in internal energy as follows.
= 12,900 J - (-2,380 J)
= (12,900 + 2,380) J
= 15,280 J
Thus, we can conclude that the change in internal energy of the system is 15,280 J.