Answer:
cos
θ
=
−
√
1
−
9
25
cos
θ
=
−
√
25
25
−
9
25
cos
θ
=
−
√
16
25
=
−
4
5
Step-by-step explanation:
B. 24 mm squared
C. 42 mm squared
D. 48 mm squared
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To find the area of the shaded region, we must find the area of the inner white triangle and subtract it from the area of the outer blue one.
Outer:
A = bh
A = (12 · 5)
A = (60)
A = 30 mm²
Inner:
A = bh
A = (4 · 3)
A = (12)
A = 6
30 - 6 = 24
Answer:
43/20 = 2 3/20
Answer:
2 3/20
Step-by-step explanation:
First you would write 2.15/1 ; Next, multiply both the bottom and the top by 100 because of the decimal placement. This gives you 215/100. Find the GCF (which is 5) and divide. This leaves you with 43/20, and when simplified, gives you 2 as the whole number and 3/20.
Answer:
4x = 4x+8
4x-4x=8
0=8
the equation is wrong
∅
Step-by-step explanation:
Segment MN is congruent to segment PQ, and angles O and R are congruent.
Segment NO is proportional to segment QR, and angles M and P are proportional.
Segment MN is congruent to segment PQ, and angles O and R are proportional.
Answer:
Option 1 is correct.
Step-by-step explanation:
Given if If triangle MNO is similar to triangle PQR, we have to choose the true statement about the two triangles.
As the two triangles are similar therefore their corresponding sides are proportional angle angles are congruent.
In the option 1,
Segment NO is proportional to segment QR, and angles M and P are congruent.
which is the correct option.
Option 2: Segment MN is congruent to segment PQ, and angles O and R are congruent.
If two triangles are similar then its not compulsory corresponding sides are congruent these are proportional.
Not correct.
Option 3: Segment NO is proportional to segment QR, and angles M and P are proportional.
here, angles must be congruent.
Not correct.
Option 4: Segment MN is congruent to segment PQ, and angles O and R are proportional.
If two triangles are similar then its not compulsory corresponding sides are congruent these are proportional.
Not correct.
The quadratic function A in standard form to represent the combined area A of the picture and the frame is 4w²+32w+55.
Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
We have,
Nicky wants to surround a painting 5 inches by 11 inches with a frame that is w inches wide.
Then, the width of the painting
w = 5 + w + w
=2w+5 (w inches wider on both sides)
and, the length of the painting
l = 11 + w + w = 2w+11
So, the area is
Area = length x width
= (2w+11)(2w+5)
=4w²+22w+10w+55
= 4w²+32w+55
Learn more about Equation here:
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Answer:
Since the frame is uniform around the picture, you need to add its width, W, to the sides of the picture. We will manipulate the formula for area, A = L x W. To ease confusion with the chosen variable, I will replace the W with an H for height to be A = L x H.
L = W + 11 + W
H = W + 5 + W
You can see this by drawing a picture with a frame around it. Looking from the top to the bottom, you will have it's width plus the picture plus the width of the frame again. Same thing for the height of the picture. Looking from the far left of the frame and across, you have the width of the frame plus the picture plus the width of the frame again. Now plug these into the area formula and combine like terms.
A = L x H
A = (W + 11 + W) x (W + 5 +W)
A = (2W + 11) x (2W + 5)
Now take the product of the two parenthesis.
I learned to use the FOIL method: multiply First, Outside, Inside, Last.
A = (2W x 2W) + (2W x 5) + (11 x 2W) + (11 x 5)
A = 4W2 + 10W + 22W + 55
A = 4W2 + 32W + 55
Step-by-step explanation: