What is the positive difference between the square of the sum of the first five positive integers and the sum of the first five positive perfect squares?

Answers

Answer 1

Answer:

The positive difference between the square of the sum of the first five positive integers and the sum of the first five positive perfect squares is 170. This is obtained by taking the sum of first five numbers, squaring the sum and subtracting the sum of first five perfect squares.

Calculate the positive difference:

The sum of first five positive integers = 1+2+3+4+5 = 15

Square of the sum of the first five positive integers = 15² = 225

The sum of the first five positive perfect squares =1²+2²+3²+4²+5²

=1+4+9+16+25

=55

The positive differenece = 225-55=170

Hence the positive difference between the square of the sum of the first five positive integers and the sum of the first five positive perfect squares is 170.

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Answer 2

Answer:

Answer:

200

Step-by-step explanation:

The square of the sum of the first five positive integers:

(1 + 2 + 3 + 4 + 5)² = 15² = 225

The sum of the first positive perfect square:

1² + 2² + 3² + 4² + 5² = 1 + 4 + 9 + 16 + 25 = 55

225 - 55 = 200

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Answers

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Answers

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Answers

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At top speed, a coyote can run at a speed of 44 miles per hour. if a coyote could maintain its top speed, how far could it run in 15 minutes?A- 2.93 miles
B- 11 miles
C- 176 miles
D- 660 miles

Answers

Answer:

Option B is correct

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Step-by-step explanation:

Using formula:

$\text{Distance} = \text{Speed} * \text{Time}$

As per the statement:

At top speed, a coyote can run at a speed of 44 miles per hour.

⇒Speed = 44 miles per hour

It is also given that:

Time = 15 minutes

Use conversion:

1 minute = $(1)/(60)$ hours

then;

15 minutes = $(15)/(60) =(1)/(4)$ hours

Substitute the given values in the formula we have;

$\text{Distance} = 44 * (1)/(4) = 11$ miles

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Answers

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Answers

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