Justine is a wedding coordinator. She is selecting the menu options for the reception

Answers

Answer 1
Answer: What does she want on the menu

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Beulah used 3/5 pounds of dough, 3/4 pound of sugar, & 2/3 pounds of sprinkles to make donuts. How many pounds of donuts did Beulah make?

Answers

Number of pounds of dough used = 3/5 pounds.

Number of pounds of sugar used = 3/4 pounds

Number of pounds of sprinkles used = 2/3 pounds.

Total number of pounds of donuts = Number of pounds of dough used + Number of pounds of sugar used + Number of pounds of sprinkles used.

Plugging values.

Total number of pounds of donuts = 3/5 + 3/4 + 2/3.

We need to add all those fractions.

In order to add fracions, we need to find common denominator (lcd).

We have 5,4 and 3 in denominators.

Least common denominator(lcd) of 5, 4 and 3 is 60.

We need to make each denominator equals 60.

Multiplying first fracion by 12 in top and bottom, we get

3*12/5*12 = 36/60

Multiplying first fracion by 5 in top and bottom, we get

3*15/4*15 = 45/60

Multiplying first fracion by 20 in top and bottom, we get

2*20/3*20 = 40/60.

Therefore,

3/5 + 3/4 + 2/3 = 36/60 + 45/60 + 40/60

               =  121/60

Let us convert 121/60 into mixed fraction.

Dividing 121 by 60 we get quotient =2 and remainder =1.

So, the mixed fraction is 2 1/60.

Therefore, Beulah made total 2 1/60 pounds of donuts.

Final answer:

The total weight of the donuts can be found by adding together the weights of the dough, sugar, and sprinkles, which comes to approximately 2.02 pounds.

Explanation:

The total weight of the donuts Beulah made can be found by adding the weights of the ingredients - dough, sugar, and sprinkles - together. First, she used 3/5 pounds of dough, to which she added 3/4 pound of sugar. Lastly, she used 2/3 pounds of sprinkles.

Now, let's add these quantities:

  • 3/5 + 3/4 + 2/3 = 1.2 + 0.75 + 0.67 approximately.
  • Alternatively use a common denominator (60 for instance) to simplify the addition:
  • 36/60 + 45/60 + 40/60 = 121/60 =2.02 pounds approximately.

Therefore, "Beulah made about 2.02 pounds of donuts".

Learn more about Quantity Addition here:

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Solve equation 19 - h - h = -13

Answers

Answer:

h = 16

Step-by-step explanation:

to solve this equation

we are going to take cognizance of the positive and negative sign as any misinterpretation of the sign might influence our answer wrongly. Note this

negative × negative  = positive

positive × negative = negative

negative × positive = negative

positive × positive = positive

so, from the question 19 - h - h = -13

19 - h - h = -13

19 -2h = -13

collect the like terms

19 + 13 = 2h

32 = 2h

divide both sides by the coefficient of h which is 2

32/2 = 2h/2

16 = h

therefore h = 16

Determine how many points the parabola has in common with the x-axis and whether it's vertex lies above, on, or below the x-axis.

Answers

Points "in common with the x-axis" are also known as the roots of the quadratic equation x^2-12x+12=0. You can apply the quadratic root formula to determine the roots, and also to determine how many such roots there are. With a quadratic (whose graph is a parabola), there can be maximum of 2 roots. But under certain circumstances, there may be only one or no such root.

The root formula for a generic quadratic ax^2+bx+c is as follows:

x_(1,2)=(-b\pm√(b^2-4ac))/(2a)

The expression b^2-4ac under the square root is called the determinant. It is called so because it determines the number of real roots. If the determinant value is > 0, there will be 2 roots (and so the parabola will cross the x-axis in 2 points), if its value is =0, there will be only a single root (the the parabola will touch the x-axis in exactly one point), and, finally, if its value is < 0, the quadratic has no real root (andthe parabola will not have any x-intercepts).

So, let's take a look:

b^2-4ac= (-12)^2-4\cdot 1\cdot12=96

This means the parabola will intercept the x-axis at 2 points, two real roots.

Since the coefficient of the quadratic term is positive (a=1), the parabola is oriented "open-up." But since we already know the parabola intercepts in two points, the fact that it is open-up implies now that the vertex must lie below the x-axis (otherwise it could not intercept it).

Figure A is a scale image of figure b. What is the value of X?

Answers

Answer:

x = 4.4

Step-by-step explanation:

To determine the scale factor, calculate the ratio of corresponding sides, image to original, that is

(x)/(11) = (4)/(10) ( cross- multiply )

10x = 44 ( divide both sides by 10 )

x = 4.4

I REALLY NEED HELP PLZ!!!! PICTURE DOWN BELOW!the graph represents the last five years of computer hard drive production for Quality hard disks.
Part A
the variable T represents the time (in years). List the ordered pairs for t = 1 and t= 2
Part B
write an equation to represent the relationship between the time, t, and the number of hard disk produced ,p.

Answers

Part A:
To do this you have to find where t=1 and where 1=2. Then you have to go up the y axis (the vertical axis) until you hit a dot. For example, t=1, from t=1 you go up until you reach the dot which is located a 1,200. Then the ordered pair is (x [number of hard disks produced] ,y [time]) so it would be (1,1200)
Part B:
To do this you have to find a pattern between the x and the y coordinates. Easiest way is to divide the y by the x and see fi that works for all of the points.  Example: (1,1200) 1200/1=1200 (2,2400) 2400/2=1200. Bingo! The relationship is multiple the x (t) coordinate by 1200. The equation would look like this: 1200t=p

Solve

x2 + 6x + 6 = 0

Answers

Answer:

The solution of x^2 + 6x + 6 is x = -1.2679 or -4.7320

Solution:

A two degree polynomial equation is given in the question.

We have been asked to solve it to find the value of ‘x’.

The given equation is:

x^(2)+6 x+6=0

There are two ways to solve this equation.

We can either factorise it or use the quadratic equation formula. For factorising it, it has to satisfy certain conditions.

The condition is b^2 - 4ac should be a perfect square otherwise the equation is not factorable.

a=1,b=6,c=6

On substituting the values of a,b and c, we get:

Which is not a perfect square.

Hence we have to use the quadratic equation is

x=\frac{-b \pm \sqrt{b^(2)-4 a c}}{2 a}

By substituting the values of a,b and in the quadratic equations. We get;

\begin{array}{l}{x=\frac{-6 \pm \sqrt{6^(2)-4 * 1 * 6}}{2 * 1}} \n\n {x=(-6 \pm √(12))/(2 * 1)}\end{array}

The two roots of x are:

\begin{aligned} x &=(-6-√(12))/(2 * 1) \n\n x &=(-6+√(12))/(2 * 1) \end{aligned}

On solving both the equations we will get the roots of the given equation, which are:

x = -1.2679 or -4.7320

Answer:

-1.2679 or -4.7320

Step-by-step explanation: