MATHEMATICS HIGH SCHOOL

Which represents the inverse of the function f(x) = 4x?h(x) = x + 4
h(x) = x - 4
h(x) = 2x
h(x) = IX
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Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

(1) = f(x) = 4x

y = 4x\nx = 4y\ny = (x)/(4)\nf^(-1)(x) = (x)/(4)

(2) h(x) = x + 4

y = x + 4

Replace x with y and vice versa:

x = y + 4

And then solve for 'y':

y = x - 4

h^(-1)(x) = x - 4

(3) h(x) = x - 4

y = x - 4

x = y - 4

y = x + 4

h^(-1)(x) = x + 4

(4) h(x) = 2x

y = 2x

x = 2y

y = (x)/(2)

h^(-1)(x) = (x)/(2)

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What is the perimeter of a basement floor that is 40 feet long and 24 feet wide

Answers

We are going to add. 40+40=80 \ and \ 24+24=48 80+48=128. So the perimeter is 128. Hoped I helped. :)
So, what you do is
40 + 40 = 80
24 + 24 = 48
80 + 48 =128cm

Help me solve this problem please

Answers

Answer:

c

Step-by-step explanation:

4. Find the length of side EG.

Answers

Answer:

42 cm

Step-by-step explanation:

the first triangle is 7 times bigger than the second triangle. ( 4 x 7 = 28)

so to find out line EG, you times 6 cm by 7. which is 42

So this is the pic that i took cause the first one was blurred

Answers

Simple....

so for the first one...

it's asking what m<KLM is if m<KLB=26 and m<BLM=

Find three consecutive odd numbers whose sum is 303

Answers

n;\ n+2;\ n+4-three\ consecutive\ odd\ numbers\n\nn+(n+2)+(n+4)=303\n\n3n+6=303\n\n3n=303-6\n\n3n=297\ \ \ \ /:3\n\nn=99\n\nAnswer:99;\ 101;\ 103.
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Solve: sec b cosec b=2 cosec b

Answers

Answer:

b = 60° or 300°

Step-by-step explanation:

We can solve the equation sec b csc b=2 csc b in terms of sin and cos as follows:

We can write sec b and csc b in terms of sin and cos:

\sf sec \:b = (1)/(\:cos\: b)

\sf csc b = (1)/(sin \:b)

Substituting these expressions into the equation, we get:

\sf (1)/(cos b) \cdot (1)/(sin b) = 2 \cdot (1)/(sin b)

Multiplying both sides of the equation by sin b cos b, we get:

\sf 1 = 2\cdot (cosb\cdot sinb)/(sinb)

\boxed{\sf (sin b)/(sinb)=1}

so,

\sf 1 = 2\: cos b

Dividing both sides of the equation by 2, we get:

\sf (1)/(2) =cos b

\sf cos 60^\circ = cos b

Since cos is positive in 1st and 4th quadrant, so

\sf cos 60^\circ \:\:or\:\:cos(360^\circ-60^\circ)= cos b

Therefore, the solutions to the equation sec b \csc b=2 \csc b for b is 60° or 300°
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