A photograph club has 100 members and 45 are women what fraction of the members represent women

Answers

Answer 1
Answer: It could be 45/100 but I'm sure you can simplify it.

Related Questions

4x+3y=12 in y=mx+b form
Match the terms to their definition. 1. consistent equations the determinant found when column 1 consists of the constants and column 2 consists of the y-coefficients of a linear system 2. equivalent equations the determinant found when column 1 consists of the x-coefficients and column 2 consists of the constants of a linear system 3. inconsistent equations equations having a common solution in a system 4. linear inequality equations having no common solutions in a system 5. substitute replace a quantity with its equal 6. system determinant equations having all common solutions 7. x-determinant an open sentence of the form Ax By C < 0 or Ax By C > 0 8. y-determinant the determinant found when column 1 consists of the x-coefficients and column 2 consists of the y-coefficients of a linear system
What is the value of 64 ÷ 2 ∙ 16.
PLEASE HELP! 80 POINTS AND BRAINLIEST TO FIRST ANSWER! A rectangular pen is constructed with 300m of fencing against a barn wall. What dimensions give the maximum area?
Bruno bought 96 pounds of sugar for his bakery. Every day he used the same amount of sugar to make bakery items. After 10 days, Bruno was left with 15.2 pounds of sugar. On average, how many pounds of sugar did Bruno use each day? 5.60 pounds 8.08 pounds 11.12 pounds 18.46 pounds

Which is greater 6.8 or 8.6?

Answers

8.6 because 8 is bigger than 6
8.6 is greater than 6.8 because the whole number in front of the decimal point (8) is greater than the whole number in front of the decimal point (6).

Which graph represents the solution set of the system of inequalities?

Answers

Answer:

D (right-down graph)

Step-by-step explanation:

y = ax+b - linear function,

a>0 - ascending

a<0 - descending

y=\frac13x-3 - ascending function, because a=\frac13, so a>0

y=-3x-3 - descending function, cause a=-3, so a<0

We refuse both graphs on the left side, these are two ascending functions

y\ge\frac13x-3 is the area above the ascending function y=\frac13x-3

y<-3x-3 is the area below the descending function

This causes that D (right-down graph) is a correct answer

How do i solve and graph 5x- y \geq 5

Answers

one way is to make it into slope intercept form which is
y=mx+b
m=slope
b=y intercept or where the line will go though the y axis
treat the equal to or greater than sign as equals for now

5x-y=5
subtract y from both sides
5x=5+y
subtract 5
5x-5=y
put the sign back in
5x-5 ≥ y
reverse
y ≤ 5x-5

one way is to subsitute values and get values out so
if x=1 then
y≤5(1)-5
y≤0
(x,y)
(1,0)
(2,5)
(3,10)
(4,15)
(0,-5)

plot the points
then the ≤ sign
since ther is an underline, that means that the points are included so draw a solid line through the points

then figure out which side to shade on
the easy way is, is the point (0,0) a solution?
subsitute
0 ≤ 5(0)-5
0 ≤ -5
false so we shade the section that does not include the point (0,0) in it
the graph would look like this attachment


    (you have to put y alone {Ex: y = 12x + 3 (yis alone on one side)}



5x - y 
≥ 5       (subract 5x from each side)
-y ≥ -5x + 5   (divide - or -1 from each side)  Note: when you are dividing or multiplying anything negative the sign changes
≤ 5x - 5 <--- answer


As for graphing you take the equation and graph it normally, but with a slight change. since y is less than or equal to 5x - 5, you have to color on the spACE BELOW the graphed line.

see picture:




Need help in solving this problem. Section is under limits at infinity, horizontal asymptotes...(a) A tank contains 5000L of pure water. Brine that contains 30g of salt per liter of water is pumped into the tank at a rate of 25L/min. Show that the concentration of salt after t minutes (in grams per liter) is
C(t)+ 30t/200+t
(b) what happens to the concentration as t--> infinity?

Answers

 (a) you can show the concentration by: 

amount of salt / amount of water 


amount of salt 

= 30g / L 

= [ 30 * 25g ] / [ 25L ] , 25L = 1 min 

= [ 30 * 25g ] / min 


amount of water 

= 5000 + 25t 


[ 30 * 25t ] / [ 5000 + 25t ] 

= [ 30 * 25t ] / 25*[ 200 + t ] 

= 30t / [ 200 + t ] yeah 


(b) 


lim t->∞ [ 30t / ( 200 + t ) ] 

= lim t->∞ [ ( (1 / t) * 30t ) / ( (1 / t) * ( 200 + t ) ) ] 

= lim t->∞ [ 30 / ( (200 / t) + 1 ) ] 

= 30 / ( (200 / ∞) + 1 ) 

= 30 / 1 

= 30


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Plzzzz help me with this question ❓​

Answers

Answer:

i think u should first givr her discount by doing 20/100×3500=700 and than he will get 5 percent profit than here

3500-700=2800

now for 5 % profit

5/100*2800=140

hence

20% discount=700

5% profit =140

it might be wrong but here u go

A sailboat’s sail has three sides that are all the same length. Each side measures x−10 units. The sail’s perimeter is 63 units.What is the value of x?

Answers

63/3=21
1 sail =21
21+10=31
x=31