In the number 555,55 each digit is a 5 but value of rachis different based on its place in the number. How does the value of 5 in the tents place compare to the value of the underline digit 5

Answers

Answer 1

Answer: As you move from each place to the left one place, the value increases by 10. If you move right a place, the value decreases by 10.

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What is the answer to 1/4+4/5(3/4x-1 1/9)

Answers

i got this with the info you gave me 108x-131 / 180

PLease help and best gets brainliest.School is 2 miles from home along a straight road. The table shows your distance from home as you walk home at a constant rate.

Time(mins): 10-20-30
Distnce(mi)1.5-1-0.5

1)Is the relationship in the table
proportional?
2)Find your distance from school fro each time in the table
3)Write an equation representing the relationship between the distance from school and time walking.

Answers

Part 1) Is the relationship in the table proportional?

Let

y-------> your distance from home in miles

x-------> the time in minutes

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

Let

$A(10,1.5)\nB(20,1)$

Find the slope AB

the slope is equal to

$m=((y2-y1))/((x2-x1))$

Substitute the values

$m=((1-1.5))/((20-10))$

$m=((-0.5))/((10))$

$m=-0.05$

Find the equation of the line with m and the point A

$y-y1=m(x-x1)$

$y-1.5=-0.05*(x-10)$

$y=-0.05x+0.5+1.5$

$y=-0.05x+2$

therefore

The answer part 1) is

the relationship in the table is not proportional

Part 2) Find your distance from school fro each time in the table

for

$x=10\ minutes\ny=1.5\ miles\n distance\ from\ school= 2-1.5=0.5\ miles$

for

$x=20\ minutes\ny=1\ miles\n distance\ from\ school= 2-1=1\ miles$

for

$x=30\ minutes\ny=0.5\ miles\n distance\ from\ school= 2-0.5=1.5\ miles$

Part 3) Write an equation representing the relationship between the distance from school and time walking

Let

y-------> your distance from school in miles

x-------> the time in minutes

$A(10,0.5)\n B(20,1)$

Find the slope AB

the slope is equal to

$m=((y2-y1))/((x2-x1))$

Substitute the values

$m=((1-0.5))/((20-10))$

$m=((0.5))/((10))$

$m=0.05$

Find the equation of the line with m and the point A

$y-y1=m(x-x1)$

$y-0.5=0.05*(x-10)$

$y=0.05x-0.5+0.5$

$y=0.05x$

therefore

the answer part 3) is

$y=0.05x$

1) Yes, the relationship in the table is proportional. If, when you've been walking for 10 minutes, you are 1.5 miles away from home, and when you've been walking for 20 minutes, you are 1 mile away from home, and when you've been talking 30 minutes, you are 0.5 miles away from home, then we can see that there is a proportion that happens here. For every 10 minutes you walk, you get 0.5 miles closer to your home.

2) We know that you've been walking 10 minutes already at the start of this problem, and we know that you walk at a steady pace of 0.5 miles every 10 minutes, so we just need to add 0.5 miles to our starting point to get the distance from the school to home, which makes it 2 miles away.

3) An equation representing the distance between the distance from school and time walking could be something like this:

t = 20d

Where t is the amount of time it takes to get home (in this case, t = 40 minutes) and d is the distance you can walk in 10 minutes (in this case, 0.5 miles)

The equation is lame, but that's the best I could do :\
Hope that helped =)

How much ft is in 3 miles

Answers

Hey Giraffe111!
5280 ft= 1 mile
x ft= 3 mile
5280*3=15840 ft!
I hope this helps;)

If $240 is invested at an interest rate of 9% per year and is compounded monthly, how much will the investment be worth in 14 years?$68.39
$704.28
$842.13
$846.10

Answers

Answer:

Option $\$842.13$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+(r)/(n))^(nt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=14\ years\n P=\$240\n r=0.09\nn=12$

substitute in the formula above

$A=\$240(1+(0.09)/(12))^(12*14)=\$842.13$

it is 842.13.............................

I would like to know if 2 kg is greater or less then 1500 g

Answers

1 kg = 1000 g
so 2 kg is greater than 1500 g

2 kg = 2000 g
2000 g > 1500 g

2 kg is greater than 1500 g

Leena bought 14 yards of wire. How many inches of wire did she buy? (1 yard = 36 inches)?A.)36 in.
B.)14 in.
C.)360 in.
D.)504 in.

Answers

The number of inches of wire which is equivalent to the 14 yards of wire is; 504in.

How many inches of wire is equivalent to 14 yards of wire?

It follows from the task content that the Leena bought 14 yards of wire.

Additionally, since 1 yard of wire is equivalent to 36 inches of wire.

It therefore follows that 14 yards of wire is equivalent to; 14 × 36 = 504in.