Question in the file below. (Khan Academy)
question in the file below. (Khan Academy) - 1

Answers

Answer 1
Answer: We can suggest this equation.
(6x+x)+(6x+x)+110º+110º=360º
7x+7x+220º=360º
14x=360º-220º
14x=140º
x=140º/14
x=10º

Answer. x=10º
Answer 2
Answer: Work is attached. :D



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I need help with no. 18. can someone help me? like with how its solved, not just answer

Answers

Answer:

the answer is 7.22

Step-by-step explanation:

The answer is 7.22 use the formula that it is giving you

What is the amount saved on pants that were regularly $49.00 and are now on sale for $42.99?

Answers

$49.00 - $42.99 = $6.01.... there for the answer is 6.01
to find the answer, you would subtract 42.99 from 49.00 
the answer is $6.01
label your answer!
i hope this helps!

A pile of newspapers in Ms. McGrath’s art class was 17 3/4 inches high. Each consecutive week, for the next 5 weeks, the height of the pile of newspapers increased by 8 7/12 inches. What was the height, in inches, of the pile after 3 weeks?

Answers

If you would like to know what was the height, in inches, of the pile after 3 weeks, you can calculate this using the following steps:

17 3/4 inches + 3 * 8 7/12 inches = 71/4 + 3 * 103/12 = 213/12 + 309/12 = 522/12 = 87/2 = 43 1/2 inches

The correct result would be 43 1/2 inches.

Let

x--------> the number of weeks

y--------> the height of a pile of newspapers in inches

we know that

17(3)/(4)=(17*4+3)/(4) =(71)/(4)

8(7)/(12)=(8*12+7)/(12) =(103)/(12)

y=(103)/(12)x+(71)/(4)

To find the height after 3 weeks

Let

x=3\ weeks and substitute in the equation

y=(103)/(12)*3+(71)/(4)

y=(174)/(4)

y=43.5\ in

y=43(1)/(2) \ in

therefore

the answer is

the height, in inches, of the pile after 3 weeks is 43(1)/(2) \ in

Are the parentheses and brackets correct

Answers

Answer:

the range is correct

but the domain is [-3,3)

-3.3 is the doman of the graph

Which of the following expressions are equivalent? Justify your reasoning.4√x3

1
x−1

10√x5•x4•x2

x
1
3
•x
1
3
•x
1
3

Answers

Answer:

b and d

Step-by-step explanation:

b. 1/x^-1

=(1/x)^-1

=x

d. x^1/3 * x^1/3 * x^1/3

=x^1/3+1/3+1/3

=x^3/3

=x^1

=x....

Is the square root of 130 rational or irrational? and where would it be located on a number line?

Answers

Let's start by the easiest question, the second.

We knoa that 11^2=121\ \textless \ 130\ \textless \ 12^2=144 hence \boxed{11\ \textless \ √(130)\ \textless \ 12}

Now let's try simplifying the square root of 130 : 130=2\cdot5\cdot13, which are all prime numbers that appear only once : the square root of 130 is irrational.