1+4=5 2+5=12. 3+6=21. 8+11=?

Answers

Answer 1

Answer: Hi there this is a puzzle question. So lets get to the answer. If 1+4=5 then we take 1+(4*1)=5. 2+5=12 so lets take 2+(5*2)=12. 3+6=21 so lets take 3+(6*3)=21. After all of this you should probably know now that I multiplied the first number with the second number then added both of the numbers. So, 8+11=8+(11*8)=8+88=96. Therefore, the answer is 96.

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Mai wants to make a scale drawing of her kitchen. Her kitchen is a rectangle with length 6 m and width 2 m. She decides on a scale of 1 to 40.Draw and label the dimension of a scale drawing of Mai’s kitchen, using a scale of 1 to 40.

Answers

Answer:

Step-by-step explanation:

This is an easy problem to work out, but a little hard to explain with just words and not a drawing.

Do you understand "scale"? As in a "map scale"? So many inches equals one mile or one kilometer?

If you were to draw this kitchen at "full scale" you'd need a really big piece of paper, right? 6m by 2m at least.

But that's not very helpful, so you "scale" it down. What if you divided each measurement by 2? Then your piece of paper would 'only' need to be 3m by 1m. Still too big though, right?

So cut each measurement in half again, and you're down to 1.5m by 0.5m. Getting better. What we just did there is a "scale of 1 to 4," often written as 1:4. (Cutting in half twice is 1/4th, or 1:4.)

But the problem specifies 1:40, so simply divide by 10 now, and you no longer need a piece of paper 1.5m x 0.5m, but only 0.15m (15cm) by 0.05m (5cm).

So on a piece of paper and draw a line 15cm long. That's the scaled graphical representation of the long side of Mai's kitchen. 6m in the real world is 600cm. Divide that by the "scaling factor" of 40 to get 15cm that you draw on your paper.

The other side of her rectangular kitchen scales down to 5cm. (200cm/40). So add that as the short leg, then complete the other two sides of the rectangle.

When they say to scale something down, simply divide all the dimensions by the scaling factor.

(If you were to scale up, you'd multiply by the scaling factor.)

How was pre-image CDEF transformed to create image CꞌDꞌEꞌFꞌ?A. 180° clockwise rotation around point G

B. 270° counterclockwise rotation around point G

C. reflection over segment CF

D. translation 2 units to the right

Answers

The right answer for the question that is being asked and shown above is that: "B. 270° counterclockwise rotation around point G." the pre-image CDEF transformed to create image CꞌDꞌEꞌFꞌ is that B. 270° counterclockwise rotation around point G

The correct answer for this question is A. 180° clockwise rotation around point G!!

Hope i helped look at file below:

A theater needs to place seats in rows. The function, f(r) as shown below can be used to determine the number of seats in each row, where r is the row number.f(1) = 8
f(r) = f(r – 1) + 3
Use the function to complete the table indicating the number of seats in each row for the first four rows of the theater.

Answers

The row counts start at eight and count up by three:

$f(1)=8$
$f(2)=f(2-1)+3=f(1)+3=8+3=11$
$f(3)=f(3-1)+3=f(2)+3=11+3=14$
$f(4)=f(4-1)+3=f(3)+3=14+3=17$
.
.
.
and so on.

A Pythagorean triple is a triple of natural numbers satisfying the equation a^2+b^2+c^2.One way to produce a Pythagorean triple is to add the reciprocals of any two consecutive even or odd numbers. For example, 1/5+1/7=12/35. Now 12^2+35^2=1369. This is a Pythagorean triple if 1369 is a perfect square, which it is since 1369=37^2. So 12, 35, 37 is a Pythagorean triple. Prove that this method always works.

Answers

x, x+2 - two consecutive odd or even numbers
Add the reciprocals of these numbers.
$(1)/(x)+(1)/(x+2)=(x+2)/(x(x+2))+(x)/(x(x+2))=(x+2+x)/(x^2+2x)=(2x+2)/(x^2+2x)$

Now add the squares of the numerator and denominator, as in the example.
$(2x+2)^2+(x^2+2x)^2= \n 4x^2+8x+4+x^4+4x^3+4x^2= \n x^4+4x^3+8x^2+8x+4$

So this number has to be a perfect square.
$x^4+4x^3+8x^2+8x+4= \nx^4+2x^3+2x^2+2x^3+4x^2+4x+2x^2+4x+4= \nx^2(x^2+2x+2)+2x(x^2+2x+2)+2(x^2+2x+2)= \n(x^2+2x+2)(x^2+2x+2)= \n(x^2+2x+2)^2$
It is a perfect square, so this method always works.

The numbers $2x+2, \ x^2+2x, \ (x^2+2x+2)^2$ are a Pythagorean triple for any $x \in \mathbb{N^+}$ .

Answer:

even tho this has nothing to do with the answer ;-;

Step-by-step explanation:First a definition: A Pythagorean Triple are three natural numbers 1 <= a <= b <= c, such that a2 + b2 = c2 holds. For example 3, 4, 5 is such a triple, since 32 + 42 = 9 + 16 = 25 = 52. While 2, 3, 4 is not such a triple, since 22 + 32 = 4 + 9 = 13 and 42 = 16. We note here that only natural numbers are considered, and thus 2, 3 can not be extended to Pythagorean triple (since 13 is not the square of some integer).

Now the question: Can we colour the natural numbers 1, 2, 3, ... with two colours, say blue and red, such that there is no monochromatic Pythagorean triple? In other words, is it possible to give every natural number one of the colours blue or red, such that for every Pythagorean triple a, b, c at least one of a, b, c is blue, and at least one of a, b, c is red ? We prove: The answer is No. That is easier to express positively: Whenever we colour the natural numbers blue or red, there must exist a monochromatic triple (one blue triple or one red triple).

More precisely we prove, using "bi-colouring" for colouring blue or red: 1) However we bi-colour the numbers 1, ..., 7825, there must exist a monochromatic Pythagorean triple. 2) While there exists a bi-colouring of 1, ..., 7824, such that no Pythagorean triple is monochromatic. Part 2) is relatively easy. Part 1) is the real hard thing -- every number from 1, ..., 7825 gets one of two possible colours, so altogether there are 27825 possible colourings, which all in a sense need to be considered, and need to be excluded. What is 27825? It is approximately 3.63 * 102355, that is, a number with 2356 decimal places. The number of particles in the universe is at most 10100, a tiny number with just 100 decimal places (in comparison).

Now let's perform real brute-force, running through all the possibilities, one after another: Even if we could place on every particle in the universe a super-computer, and they all would work perfectly together for the whole lifetime of the universe -- by far not enough. Even not if inside every particle we could place a whole universe. Even if each particle in the inner universe becomes again itself a universe, with every particle carrying a super-computer, still

by far not enough. Hope you get the idea -- the $100 we got wouldn't pay that energy bill.

Fortunately there comes SAT solving to the rescue, which actually is really good with such tasks -- it can solve some such task and even more monstrous tasks. Our ``brute-reasoning'' approach solved the problem and resulted into a 200 terabytes proof -- the largest math proof ever. Though we must emphasise that this is in no way guaranteed, and possibly it will take aeons! SAT solving uses propositional logic, in the special form of CNF (conjunctive normal form). Fortunately, in this case it is easy to represent our problem in this form.

A stockbroker earns a base salary of 40000 dollar plus 5%of the total value of the stocks,mutual funds , and other investments that the stockbrokersells.last year, the stockbroker earned 72750 dollar. what was the total value of investments the stockbroker sold?

Answers

Well his salary is $40,000 dollars.

$72,750 - $40,000 = $32,750

This means that 5% of the value of investments he had sold was equal to $32,750.

$\frac { 1 }{ 20 } * I=32750\n \n 20* \frac { 1 }{ 20 } * I=20* 32750\n \n \therefore \quad I=655000$

The stockbroker sold $655,000 worth of investments.

Find the value of z in parallelogram BCDE.

Answers

3z = z + 22
2z = 22
z = 11

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