which container hold the most? a. cylinder with a radius of 5 in and a height of 15 in b. sphere with a radius 6in c. come with a radius of 8in and a height of 15in

Answers

Answer 1
Answer: Vcylinder=hpir^2 Vsphere=(4/3)pir^3 Vcone=(1/3)hpir^2 Vcylinder=15*pi*5^2=375pi in^3 Vsphere=(4/3)*pi*6^3=288pi in^3 Vcone=(1/3)*15*pi*8^2=320pi in^3 greatest is Vcylinder at 375pi in^3 answer is A (cylinder)

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Please someone can help me with #3. Thanks

Answers

You plug in 8 for the r's and you'll get 8 plus 8 divide by 2 times 4  then youll get 8+4 times 4. Then you'll get 8+16 and it --24
r + r ÷ 2 × 4 when r = 8.


8 + 8 ÷ 2 × 4  
8 + ___ × 4  
8 + ___
      ___

Lets solve for the missing. 

8 + 8 ÷ 2 × 4
8 ÷ 2 = 4
8 + × 4
4 × 4 = 16
8 + 16
8+16 = 24

SO:-
 


8 + 8 ÷ 2 × 4  
8 + _4_ × 4  
8 + _16__
      _24__

So, r + r ÷ 2 × 4 when r = 8 is 24.

Hope I helped ya!! xD

Howcto write 9,000,009 in word form

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nine million and nine

For 1 and 2 use the number lines given to complete the number

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1/3 for the first one, and 3/4 for the second one :)
For the first one its 1/3 and the second one is 3/4

What is the slope of the line shown below?10
(6,2)
10 (-2,-3)
10
10-
O
A.
olm
O
B.
LOCO
O c.
D.
O
100
Helpppppp

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The answer is D, 5/8

Compare and contrast the Pythagorean theorem, a circle, and the distance formula

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Answer:

The distance formula is a formalization of the Pythagorean Theorem using x and y coordinates. In other words, they are the same thing in two seemingly different contexts. Every point (x,y) on the circle is related to the circle's center (a,b) by the fact that the distance between the point and the center is a constant (the radius of the circle, r).  Equation of a circle is exactly the Pythagorean theorem with specific values plugged in.

Step-by-step explanation:

Find a degree three polynomial having zeros -6, -8 and -3 and a leading coefficient equal to one

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Answer:

Step-by-step explanation:

hello  :

f(x) = (x+3)(x+6)(x+8)