Answer:
1. 12 bags for total cost of 119.88
2. Yes. You'll make $180.12 for your labor.
3. Other tools, transportation, weather delay etc.
4. $28.02
5. Yes
Step-by-step explanation:
Begin by finding the area of the field. The field is a rectangle and measures 360 by 160. The area is A = l*w = 360*160 = 57,600 square feet. One bag of fertilizer will cover 5000 square feet. Divide 57,600 by 5000 to find the number of bags needed. You'll need 11.52 bags or rounded 12 bags.
Since each bag costs $9.99, multiply 12 by $9.99 to get the total cost for the fertilizer. The cost is $119.88. If the athletic department pays you $300. You'll make 300 - 119.88 = 180.12 for your labor. This is a good profit.
If you have to purchase another tool for $40, then the cost increases to 159.88. This decreases your profit to 180.12 - 40 = 140.12. Divide your profit 140.12 by the 5 hours you work to find how much you earn per hour. You earn $28.02 per hour.
Yes, I would take the job, since $28.02 is well above minimum wage.
Answer:x = 3
Step-by-step explanation:
2(5x-7)=2x+10
distribute 2(5x-7)
=2*5x - 2*7
∨ ∨
10x - 14
10x - 14 = 2x + 10
add 14 to both sides
10x-14=2x+10
+14 +14
simplify
10x=2x+24
subtract 2x to both sides
10x=2x+24
-2x -2x
simplify
8x=24
divide both sides by 8
8x=24
÷8x ÷ 8x
x = 3
The value of percent error of the odometer is, 12%.
A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.
We have to given that;
The odometer recorded 13.2 miles for his last trip to the hardware store.
But he knows the distance traveled is 15 miles.
We know that;
The percent error = (Measured value - Actual value) / actual value × 100
Here, The actual value = 15 mile
And, The measured value = 13.2 mile
So, The percent error is,
⇒ Percent error = |13.2 - 15| / 15 × 100
= 1.8/15 × 100
= 12%
Learn more about the percent visit:
#SPJ2
12 percent is the error.
.
What about y=6
Please explain :)
Answer:
y = 4x + 6
Step-by-step explanation:
2 = 4[-1] + b
-4
6 = b
If you are ever in need of assistance, do not hesitate to let me know by subscribing tomy You-Tubechannel[USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.
**In one of my You-Tube videos, I have a video that kind of talks about something like this. I encourage you to watch it and gain more knowledge.