How could you describe this graph?
How could you describe this graph? - 1

Answers

Answer 1
Answer:

Skewed right, if its data is mostly on the left it’s skewed right, if it’s data is mostly on the right it’s skewed left

Answer 2
Answer:

Answer: skewed right

Step-by-step explanation:


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80% of what # is 16?

Answers

80% of x = 16
"of" translates to multiplication and 80% becomes 80/100.

80/100 × x = 16

0.8x = 16

0.8x/0.8 = 16/0.8

x = 16/0.8

x = 20


Your final answer is 80% of 20 is 16.

How far can your brother get if he can travel at 2.5 m/s and in 5 seconds you will discover that his squirt gun had run out of paint

Answers

Answer:

12.5 meters

Step-by-step explanation:

2.5 m/s for 5 seconds is

2.5*5=12.5

12.5 m after 5 seconds

Simplify: 6 3/4 × 3 1/2 ÷ 3 3/5 ÷ 3 3/4

Answers

Answer:1 3/4

Step-by-step explanation:

6 3/4*3 1/2 divided 3 3/5 divided 3 3/4

convert to proper fraction

27/4*7/2 divided 18/5 divided 15/4

27/4*7/2*5/18*4/15= 63/36= 7/3

27/4 × 7/2 ÷ 18/5 ÷ 15/4
= 27/4 × 7/2 × 5/18 × 4/15
= 3780/ 2160
= 21/12

= 7/3

Help please! this is due tomorrow so please help out! will mark as brainiest!!

Answers

Answer:

\large\boxed{\bold{Q1}\ -(128)/(9)}\n\boxed{\bold{Q2}\ 2^(25)}

Step-by-step explanation:

\bold{Q1}\n\n(-2(3^2\cdot3^3)^2)/(3^(12)\cdot2^(-6))\qquad\text{use}\ a^n\cdot a^m=a^(n+m)\n\n=-(2(3^(2+3))^2)/(3^(12)\cdot2^(-6))=-(2(3^5)^2)/(3^(12)\cdot2^(-6))\qquad\text{use}\ (a^n)^m=a^(nm)\n\n=-(2\cdot3^(5\cdot2))/(3^(12)\cdot2^(-6))=-(2\cdot3^(10))/(3^(12)\cdot2^(-6))\qquad\text{use}\ (a^n)/(a^m)=a^(n-m)\n\n=-2^(1-(-6))\cdot3^(10-12)=-2^(7)\cdot3^(-2)\qquad\text{use}\ a^(-n)=(1)/(a^n)\n\n=-2^7\cdot(1)/(3^2)=-(2^7)/(3^2)=-(128)/(9)

\bold{Q2}\n\n(4^2)/(4^(-7))\cdot(2^4\cdot2^3)\cdot(3^(-2))^0\qquad\text{use}\ (a^n)/(a^m)=a^(n-m),\ a^n\cdot a^m=a^(n+m),\ a^0=1\n\n=4^(2-(-7))\cdot2^(4+3)\cdot1=4^(9)\cdot2^7=(2^2)^(9)\cdot2^7\qquad\text{use}\ (a^n)^m=a^(nm)\n\n=2^(2\cdot9)\cdot2^7=2^(18)\cdot2^7\qquad\text{use}\ a^n\cdot a^m=a^(n+m)\n\n=2^(18+7)=2^(25)

(3x^-2y)*(8xy^-3) --- SOLVE

Answers

(3x^2-2y)*( 8xy ^(-3) )

Remove parentheses : (a) = a

= (3x^2-2y) * 8xy ^(-3)

y^(-3)

Apply  expoent rule

 a ^(-b) = (1)/(a ^(b) )

= (1)/(y^3)

8x (1)/(y^3) (3x^2-2y)

Multiply fractions:

a* (b)/(c) = (a*b)/(c)

= (8(3x^2-2y))/(y^3)

hope this helps!

1 Use Negative Power Rule: xa=1xax−a=1xa
3×1x2y×8xy33×1x2y×8xy−3
2 Use Negative Power Rule: xa=1xax−a=1xa
3×1x2y×8x×1y33×1x2y×8x×1y3
3 Simplify
24yxx2y324yxx2y3
4 Use Quotient Rule: xaxb=xabxaxb=xa−b
24y13x1224y1−3x1−2
5 Simplify 131−3 to 2−2
24y2x1224y−2x1−2
6 Simplify 121−2 to 1−1
24y2x124y−2x−1
7 Use Negative Power Rule: xa=1xax−a=1xa
24×1y2x124×1y2x−1
8 Use Negative Power Rule: xa=1xax−a=1xa
24×1y2×1x24×1y2×1x
9 Simplify
24y2x24y2x

Can someone put this in order

Answers

So in order to figure this out we need to know the formula for simple interest
In this case it is. 
I = p r t  (they are all multiplied by each other) 

p = "principle" or the starting amount of money
r = the rate or percentage
t = time (in years)
So lets figure it out in the order they give it to us. Then Put them least to greatest. 

So the first one is 
Investment at $3,000 at 16% simple interest for 2 years. 
We multiply them all together to get our interest. 
lets do the math:) 
16% = 0.16 
$3,000 x 0.16 x 2 = $960

Now lets do the second one.
Investment of $3,000 at 5% simple interest for 20 years. 
Lets multiply them all together. 
5% = 0.05 
$3,000 x 0.05 x 20 = $3,000

Now for our third one. 
Investment of $1,000 at 16% simple interest for 20 years 
Lets multiply them together. 
16% = 0.16 
$1,000 x 0.16 x 20 = $3,200

Now here is our answer ↓↓↓

Now to put these in order from least to greatest. 
1st.) Investment at $3,000 at 16% simple interest for 2 years. = $960
2nd.) 
Investment of $3,000 at 5% simple interest for 20 years.= $3,000
3rd.)Investment of $1,000 at 16% simple interest for 20 years.= $3,200