I Prove that Cos(90-θ)/1+sin(90-θ) +1+sin(90-θ) /cos(90-θ) =2

Answers

Answer 1

Answer: Okay,

so first you gotta know that cos(90-x) is equal to sinx and sin(90-x) is equal to cosx!!
Now all you gotta do is replace the cos(90-x) to sinx in the numerator and sin(90-x) to cosx in the denomenator inorder to make the numerator all into sin and denomenator all into cos.
After that, open up the brackets and solve...
At the end you'll hopefully get something like this :( 1+sin90 ÷ 1+cos90 )
And since sin90 is 1 (put it in the calculator!) and cos90 is 0, you'll get 2÷1 which is equals to 2!!

Hope this helped! :)

Answer 2

Answer: $(cos(90 - \theta))/(1 + sin(90 - \theta)) + (1 + sin(90 - \theta))/(cos(90 - \theta)) = 2$
$((cos(90 - \theta))(cos(90 - \theta)))/((1 + sin(90 - \theta))(cos(90 - \theta))) + ((1 + sin(90 - \theta))(1 + sin(90 - \theta)))/((1 + sin(90 - \theta))(cos(90 - \theta))) = 2$
$(cos^(2)(90 - \theta))/(cos(90 - \theta) + sin(90 - \theta)cos(90 - \theta)) + (1 + 2sin(90 - \theta) + sin^(2)(90 - \theta))/(cos(90 - \theta) + sin(90 - \theta)cos(90 - \theta)) = 2$
$(cos^(2)(90 - \theta) + 1 + 2sin(90 - \theta) + sin^(2)(90 - \theta))/(cos(90 - \theta) + sin(90 - \theta)) = 2$
$(1 + 1 + 2sin(90 - \theta))/(cos(90 - \theta) + sin(90 - \theta)) = 2$
$(2 + 2sin(90 - \theta))/(cos(90 - \theta) + sin(90 - \theta)) = 2$
$(2(1 + sin(90 - \theta)))/(cos(90 - \theta)(1 + sin(90 - \theta))) = 2$
$(2)/(cos(90 - \theta)) = 2$
$(2)/(cos(90)cos(\theta) + sin(90)sin(\theta)) = 2$

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Answers

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Answers

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Answers

In the provided data, the categorical variables are gender and car.

In the given data set, the categorical variables are characteristics that can be divided into distinct categories or groups, without considering numerical values.

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Answers

Answer:

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Step-by-step explanation:

Answer:

Y=5x+20

Because 20 is a fee that is in constant value and shouldn't be correlated with the amount of months using the subscription. 5 is the amount charged every month you keep the subscription. Y is outcome of cost, and x is the amount of months.

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Answers

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Answers

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