Answer:
y=2/5x + 7
Step-by-step explanation:
First, you have to rewrite 2x-5y=15 to slop intercept form.
To do that you have to first subtract 2x from both side to cancel it out.
2x- 2x-5y= 15 -2x.
-5y= -2x+15
Next, you divide 5 on both side to leave the y by itself.
y= -2x/-5 + 15/-5
Simplify
y= 2/5x + (-3) 2/5 is our slope
Now that we found the slope, we need to the y-intercept of line b
y=2/5x + b
To find the y-intercept, we substitue x and y with the coordinates (-10,3)
3= 2/5(-10) +b
Now we just solve for b
3= -4 +b
3-(-4) = b
7=b
Now we have identified that 7 is the y intercept
The full equation is y= 2/5x +7
I hope this helped :)
Kylie correctly understood that it is a difference of squares, but she did not determine the product correctly.
Kylie did not understand that this is a perfect square trinomial, and she did not determine the product correctly.
Kylie determined the product correctly, but she did not understand that this is a perfect square trinomial.
also elements of F.
Greetings from Brasil...
G = {4; 8; 12; 16; 20; 24; 28; 32; 36; 40; 44; 48; 52; 56; 60; 64; 68; 72; 76; 80; 84; 88; 92; 96; 100; 104; ...}
F = {1; 4; 9; 16; 25; 36; 49; 64; 81; 100; ...}
So, according to the statement, it is desired:
G ∩ F - the intersection between the 2 sets, that is, which numbers are present simultaneously in the 2 sets....
Looking at the sets we conclude that
OBS: note that in truth G are the multiples of 4
The first five elements of set H, which include positive integers divisible by 4 that are also perfect squares, are 4, 16, 36, 64, and 100.
The two sets mentioned in the problem are Set G, which contains positive integers divisible by 4, and Set F, which contains perfect squares. The intersection of these two sets is Set H. To find the elements of Set H, we look for numbers that are both divisible by 4 and perfect squares. The first five such numbers are 4, 16, 36, 64, and 100. For example, 16 is both a multiple of 4 and a perfect square because it can be expressed as 4*4 and is the square of 4. Similarly, 36 fits both criteria because it can be expressed as 4*9 and is the square of 6. We continue this pattern to identify the first five elements of Set H.
#SPJ2
Answer and then please explain what I do with the 3 and the 8.