Answer:
Pierre has enough boards and nails to make 9 tables and 5 chairs.
Step-by-step explanation:
13T+8C ≤ 220
Let us substitute 9 for T and 5 for C and check.
13(9) + 8(5) = 117 + 40
= 157 < 220
So, 220 wooden boards are sufficient to make 9 tables and 5 chairs.
48T+37C ≤ 760
Substitute 9 for T and 5 for C.
48(9)+37(5) = 432 + 185
= 617 < 760
So, 760 nails are sufficient to make 9 tables and 5 chairs.
Hence, Pierre has enough boards and nails to make 9 tables and 5 chairs.
Answer:
a.
Step-by-step explanation:
Answer:
i believe you have to divide 8 by each number to get the distance between the pairs of integers.
Step-by-step explanation:
rest are amphibians. How many more types of reptiles are there than amphibians in the exhibits?
Answer:
There are 35 more types of reptiles than amphibians
Step-by-step explanation:
112-72=40
75-40=35
The 40 is the number of amphibians and if you do the number of reptiles minus the number of amphibians (75-40) you get how many more reptiles there are than amphibians.
The zoo has 32 more types of reptiles than amphibians. This was determined by subtracting the number of amphibians from the number of reptiles.
The subject of this question is mathematics, specifically a problem requiring the subtraction operation to determine the difference between two numbers. When you are told there are 112 types of reptiles and amphibians at the zoo and 72 of them are reptiles, you are being asked to find out how many are amphibians. To do this, you simply subtract the number of reptiles from the total number of amphibians and reptiles, which is 112 - 72 = 40. Now, the student asked how many more types of reptiles there are. Since there are 72 reptiles and 40 amphibians, you would find the difference by subtracting 40 from 72, giving the result of 32. So, there are 32 more types of reptiles than amphibians at the zoo.
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