The type of stoichiometric calculation that does not require the use of the molar mass is a calculation involving molar or stoichiometric ratios which are derived directly from the coefficients in a balanced chemical equation.
In stoichiometry, there are several types of calculations that can be performed. However, the type of stoichiometric calculation that does not require the use of the molar mass is the calculation involving the molar ratio, or stoichiometric ratio. This refers to the ratio of coefficients in a balanced chemical equation, which we use to determine the relative amounts of each substance involved in a chemical reaction.
An example of this is a balanced equation for the formation of water: H2 + 0.5O2 -> H2O. In this equation, the molar or stoichiometric ratio of hydrogen (H2) to oxygen (O2) to water (H2O) is 2:1:2. If we are given the number of moles of one substance, we can use this molar ratio to find the number of moles of any other substance in the equation, without needing to know their molar masses. This constitutes a stoichiometric calculation without the need for molar mass.
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B. solution level
C. solubility level
D. saturation level
Answer:
Ionic
Explanation:
Step 1: Define
1s²2s¹ is Lithium (Li)
1s²2s²2p⁵ is Chlorine (Cl)
Step 2: RxN
2Li (s) + Cl₂ (g) → 2LiCl (s)
Step 3: Identify
LiCl is a metal and a non-metal bonded together. Therefore, it will be an ionic bond. The Lithium would transfer it's electron to Chlorine (since it wants a full outer shell 0f 8 and it currently as 7) and form a salt.
The product of 3.5 and 4.48697 is 15.705395, which rounds to 16 when using the appropriate number of significant figures.
To find the product of 3.5 and 4.48697, you would simply multiply the two numbers together. This results in 15.705395.
However, the least number of significant digits in the numbers given is two (in the number 3.5). Therefore, we will round our answer to two significant figures. 15.705395 rounds to 16 when rounding appropriately to two significant figures as we count from the first non-zero digit, which is 1, then to the next digit which is 5.
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