Answer:
The correct option is option D) 2x² + 5x - 3
Step-by-step explanation:
Simplify the expression: (x + 3)(2x - 1)
A) 7x2 - 3
B) 2x2 - 7x - 3
C) 2x2 - 5x - 3
D) 2x2 + 5x - 3
To solve the problem given, we will follow the steps below;
(x + 3)(2x-1)
We will start by opening the parenthesis
x(2x -1) +3(2x-1)
2x² - x + 6x -3
Then we can now add the values with the same coefficient
2x² + 5x -3
Therefore, the correct option is option D) 2x² + 5x - 3
Answer:
(1, -3)
(2, -5)
(3, -7)
Step-by-step explanation:
Randomly choose three values for "x". Substitute each of them separately into the formula to find the "y". Then write the solution as an ordered pair (x, y).
I will choose x=1, x=2 and x=3.
When x=1:
y = -2x - 1
y = -2(1) - 1
y = -2 - 1
y = -3
(1, -3)
When x=2:
y = -2x - 1
y = -2(2) - 1
y = -4 - 1
y = -5
(2 , -5)
When x=3:
y = -2x - 1
y = -2(3) - 1
y = -6 - 1
y = -7
(3, -7)
Three solutions for y = -2x - 1 are (0, -1), (2, -5), and (-3, 5), where x and y are related by this linear equation.
The equation y = -2x - 1 represents a linear relationship between x and y. To find three solutions for this equation, you can choose different values for x and calculate the corresponding values of y. Here are three solutions:
Solution 1:
Let x = 0:
y = -2(0) - 1
y = 0 - 1
y = -1
So, one solution is (0, -1).
Solution 2:
Let x = 2:
y = -2(2) - 1
y = -4 - 1
y = -5
So, another solution is (2, -5).
Solution 3:
Let x = -3:
y = -2(-3) - 1
y = 6 - 1
y = 5
So, a third solution is (-3, 5).
You can choose any values for x and calculate the corresponding y-values to find more solutions to this linear equation.
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Time (h) 2.5 3 5 8
Pages read 70 84 140 224
y ≥ x - 2 and y ≤ 2x - 3
y ≥ 3x - 2 and y ≤ x + 3
y ≤ 3x - 2 and y ≥ x + 3
The graph shows the solution for the inequalities y ≥ 3x - 2 and y ≤ x + 3.
The inequalities can be found by substituting the coordinates of a point within the shaded area in both inequalities and seeing if they are satisfied.
The options are given.
Let us take the options one by one:
Now, substitute (0,0) in the inequalities:
0 ≥ 2 and 0 ≤ 3
This is not true.
Now, substitute (0,0) in the inequalities:
0 ≥ - 2 and 0 ≤ - 3
This is not true.
Now, substitute (0,0) in the inequalities:
0 ≥ - 2 and 0 ≤ 3
This is true.
Now, substitute (0,0) in the inequalities:
0 ≥ - 2 and 0 ≤ - 3
This is not true.
Therefore, we have found that the inequalities are y ≥ 3x - 2 and y ≤ x + 3. The correct answer is option C.
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Answer:
and
Step-by-step explanation:
Blue:
The inequality for the blue line is
Yellow
The inequality for the yellow line is
This means that the correct answer is the third option,
and
Part B: What method is used to factor p(x)=8x3+12x2+2x+3?
Select one answer for Part A and select one answer for Part B.
B: perfect-square trinomial
B: grouping
A: (2x+3)(4x+1)
B: sum of cubes
A: (4x2+1)(2x+3)
A: (2x+3)(4x2+6x+1)
A:
B: grouping
Step-by-step explanation:
We are given the polynomial:
Part A: What is the correct factorization of over the integers?
We need to factorize the term
Factorizing by grouping:
So, factors of the term are
Part B: What method is used to factor p(x)=8x3+12x2+2x+3?
The method used to factor the given polynomial is grouping.
We group the terms and then find the common terms in that specific group
So, the answers are:
A:
B: grouping
Keywords: Finding Factors
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