Why does the addition of acid increase the solubility of calcium phosphate? a. It decreases the phosphate ion concentration, forcing the equilibrium to the right. b. It increases the phosphate ion concentration, forcing equilibrium to the left. c. It decreases the phosphate ion concentration, forcing the equilibrium to the left. d. It increases the phosphate ion concentration, forcing the equilibrium to the right. e. It decreases the calcium ion concentration, forcing the equilibrium to the right. f. It increases the calcium ion concentration, forcing the equilibrium to the right. g. It decreases the calcium ion concentration, forcing the equilibrium to the left. h. It increases the calcium ion concentration, forcing equilibrium to the left.

Answers

Answer 1
Answer:

Answer: c.  It decreases the phosphate ion concentration, forcing the equilibrium to the left.

Explanation:

The calcium phosphate in water is dissociated according to the following equilibrium:

Ca₃(PO₄)₂ ⇄ 3Ca²⁺ + 2PO₄³⁻

A neutralization reactionis one in which an acid reacts with a base. In the reaction a salt is formed and in most cases water is formed.

Phosphate is the complementary base of phosphoric acid, so when adding acid to the solution, we will neutralize the phosphate present according to the following reaction:

PO₄³⁻  + 3H⁺ ⇄ H₃PO₄

Therefore, when adding acid we increase the solubility of calcium phosphate since we are neutralizing the phosphate present in the salt, decreasing the concentration of phosphate, displacing the first equilibrium shown to the left and favoring the dissolution of calcium phosphate.

Answer 2
Answer:

Final answer:

The addition of acid to calcium phosphate decreases the phosphate ion concentration, causing a shift in equilibrium to the right, resulting in increased solubility of calcium phosphate.

Explanation:

The addition of acid increases the solubility of calcium phosphate because it decreases the phosphate ion concentration. This process forces the equilibrium to shift to the right, as per Le Chatelier's principle. This principle states that when a stress (in this case, acid addition leading to decreased phosphate ion concentration) is applied to a system at equilibrium, the system responds by shifting in a direction that minimizes that stress. In this case, the equilibrium shifts to the right, resulting in the dissolution of more calcium phosphate to replace the phosphate ions that were removed due to the addition of acid.

Learn more about Solubility of Calcium Phosphate here:

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When the pressure that a gasexerts on a sealed container
changes from 53.0 atm to 35.2
atm, the temperature changes
from
°C to 12.0°C.

Please help I will give brainliest

Answers

Answer:

To determine the relationship between pressure and temperature in this scenario, we can use the ideal gas law.

The ideal gas law states that PV = nRT, where P represents pressure, V represents volume, n represents the number of moles of gas, R is the ideal gas constant, and T represents temperature in Kelvin.

Since we only have the initial and final pressures and temperatures, we can compare them using the ideal gas law equation by setting up the following ratio:

(P₁T₁) / (P₂T₂) = (V₁n₁R) / (V₂n₂R)

Since the volume, number of moles, and gas constant remain constant, we can simplify the equation:

(P₁T₁) / (P₂T₂) = 1

Now, we can substitute the given values into the equation:

(53.0 atm * T₁) / (35.2 atm * 12.0°C) = 1

To solve for T₁, we need to convert 12.0°C to Kelvin by adding 273.15:

(53.0 atm * T₁) / (35.2 atm * (12.0 + 273.15) K) = 1

Simplifying the equation further:

(53.0 atm * T₁) / (35.2 atm * 285.15 K) = 1

Now, we can solve for T₁:

(53.0 atm * T₁) = (35.2 atm) * (285.15 K)

Dividing both sides of the equation by 53.0 atm:

T₁ = (35.2 atm * 285.15 K) / 53.0 atm

Calculating the numerical value:

T₁ ≈ 189.5 K

Therefore, when the pressure changes from 53.0 atm to 35.2 atm, the temperature changes from approximately 12.0°C to 189.5 K.

Complete the first row in the table by filling in the missing information about a system at equilibrium.A:

Q < Keq

Q > Keq

Q = Keq

Answers

Answer:

A. Q = Keq

B. Equilibrium quantities of reactants and products

C. Q > Keq

D. System will shift toward reactants

E. Overabundance of reactants

F. System will shift toward products

Here are all the answers :)

Final answer:

To fill in the table about equilibrium, if Q < Keq the reaction will move right (produce more products), if Q > Keq it will move left (produce more reactants), and if Q = Keq the system is at equilibrium with no net change.

Explanation:

To complete the first row in the table about a system at equilibrium, we need to fill in the missing information based on the reaction quotient (Q) and the equilibrium constant (Keq).

  •    

For a system at equilibrium, not only is Q = Keq, but also the change in Gibb's free energy (ΔG) is zero. This relationship can be represented as 0 ΔG° + RT ln K at equilibrium.

The marathon covers 26 miles, 285 yards. Express this distance in kilometers.(1 km= 0.6214 miles, 1 inch = 2.54 centimeters)
Show calculation steps

Answers

Answer:

Conversion gives 42,107 km in total

Explanation:

A marathon covers 26 miles and 285 yards.

If 1 kilometer is 0.6214 miles, then how many kilometers are 26 miles, then:

1 km = 0.6214 miles

X = 26 miles

X = 41,841 km

Now if 1 yard is 36 inches, how many inches is 285 yards?

1 yard = 36 inches

285 yards = X

X = 10260 inches

If an inch is equal to 2.54 cm, how many centimeters are 10260 inches?

1 inch = 2.54 cm

10260 cm = X

X = 26060.4 cm

And 26060.4 cm is 0.260604 km

Finally, the sum of the distance would be:

41.841 km + 0.260604 km = 42.107 km

How many moles are in 136.9 g of Ba(OH)2?

Answers

Answer:0.7989883138766937

Explanation:

NaOH + HCl → NaCl + H2O. What mass of water forms when 2.75 × 10–4 mol NaOH reacts completely? given the equation, 2.75 × 10–4 mol NaOH = ___ g H2O

Answers

The balanced chemical reaction is written as:

NaOH + HCl → NaCl + H2O

We are given the amount of sodium hydroxide to be used up in the reaction. This will be the starting point for the calculation. 

2.75 x 10^-4 mol NaOH ( 1 mol H2O / 1 mol NaOH ) ( 18.02 g H2O / 1 mol H2O ) = 4.96 x 10^-3 g H2O

Answer:

0.00496

Explanation:

on edg i just did the assignment teehee

Which of the measurements below best agrees with the picture?A. 35.0 mL
B. 36.5 mL
C. 36.0 mL
D. 38.0 mL

Answers

B. 36.5 mL is the correct answer