The ability of an apple to change color when exposed to air represents an example of a chemical change.
A chemical change may be defined as a type of change of materials into another form or new materials with different properties, and one or more than one new substance is formed spontaneously.
The change of color of the apple into brown when it is exposed to air is a chemical change. When you observed the color of an apple is to be brown, you are producing a chemical change. This involves the rearrangement of atoms in one or more substances resulting in a change in their chemical properties or composition.
Therefore, the ability of an apple to change color when exposed to air represents an example of a chemical change.
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We have that for the Question "What is the tension in the string connecting block 100 to block 99? What is the tension in the string connecting block 50 to block 51?"
it can be said that
From the question we are told
Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first block is pulled with a force of 100 N.
Assuming mass of each block is 1 kg
The equation for the force is given as
Now, between block 100 and 99,
Now between block 50 and 51. There are 50 blocks behind 51 st block, so,
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Answer:
The tension in the string connecting block 50 to block 51 is 50 N.
Explanation:
Given that,
Number of block = 100
Force = 100 N
let m be the mass of each block.
We need to calculate the net force acting on the 100th block
Using second law of newton
We need to calculate the tension in the string between blocks 99 and 100
Using formula of force
We need to calculate the total number of masses attached to the string
Using formula for mass
We need to calculate the tension in the string connecting block 50 to block 51
Using formula of tension
Put the value into the formula
Hence, The tension in the string connecting block 50 to block 51 is 50 N.
The angle at which the light got refracted is known as the angle of refraction. The angle of refraction of red light is 48.3°. While the angle of refraction of Violet light is 47.8°.
"The ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, for the light of a given color and for a given set of media,
According to Snell's law. The formula for Snell's law is
i is the incidence angle
r is the refractionangle.
n is the refractive index of the medium
For red light,
Hence the angle of refraction of red light is 48.3
For violet light,
Hence the angle of refraction of Violet light is 47.8°.
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Answer:
Red light has an angle of refraction of 48.3°.
Violet light has an angle of refraction of 47.8°.
Explanation:
From Snell's law of refraction, the refractive index is the ratio of the sine of the angle of incidence to the sine of the angle of refraction.
For red light in water,
For violet light in water,
With what minimum horizontal velocity must the cliff divers leave the top of the cliff if they are to miss the rock?
Answer in units of $m / s$.
Answer:
To solve this problem, we can use the kinematic equation for horizontal motion, which relates the initial velocity ($v_{0}$), final velocity ($v_{f}$), acceleration ($a$), and displacement ($d$) of an object:
$d = v_{0} t + \frac{1}{2}at^{2}$
In this case, we want to find the minimum initial velocity ($v_{0}$) that the divers must have to clear the rock. To do this, we can assume that the divers just graze the rock at the start of their trajectory, so the displacement in the horizontal direction is equal to the distance from the cliff to the rock ($d = 9.34 m$). We also know that the acceleration in the horizontal direction is zero, so the only force acting on the divers is gravity in the vertical direction, which gives an acceleration of $a = 9.8 m/s^{2}$.
At the instant the divers leave the cliff, they have zero horizontal velocity, so $v_{0} = 0$. We can use the equation above to solve for the time it takes for the divers to fall from the cliff to the level of the rock:
$d = \frac{1}{2}at^{2} \Rightarrow t = \sqrt{\frac{2d}{a}}$
Plugging in the numbers, we get:
$t = \sqrt{\frac{2(9.34 m)}{9.8 m/s^{2}}} \approx 1.44 s$
Since the cliff divers want to clear the rock, they need to travel a horizontal distance of at least $9.34 m$ during this time. We can use the equation for horizontal motion again to solve for the minimum initial velocity:
$d = v_{0}t \Rightarrow v_{0} = \frac{d}{t} = \frac{9.34 m}{1.44 s} \approx 6.49 m/s$
Therefore, the minimum horizontal velocity that the cliff divers must have to clear the rock is approximately $6.49 m/s$.
Answer:
Increasing the pitch of a note on the piano means you make the note higher