Hello from MrBillDoesMath!
Answer:
y = x - 7
Discussion:
Let's step through the answers one-by-one:
y/6 = x => multiply both sides by 6
y = 6x
y = kx where k = 6
y/x = 1/2 => multiply both sides by x
y = (1/2) x
y = kx where k = 1/2
y = -0.5x
y = kx where k = -0.5
BUT y = x -7 cannot be written simply as y = kx because of the -7 term.
Thank you,
MrB
Answer:
C. y = x - 7
Step-by-step explanation:
A. 50
B. 35
C.45
Answer:
Its c
Step-by-step explanation:
Answer:
yes it is C
Step-by-step explanation:
and
y=-3x-21
(2, -22)
(2,48)
(-2, 2)
(-2, -20)
Answer:
Please check the explanation.
Step-by-step explanation:
Given the equations
solving the system of the equations
Arrange the equation variables for elimination
solve
Divide both sides by -3
Therefore, the solutions to the system of the equations are:
But, it seems none of the options is true.
Answer:
A. (2, -22)
Step-by-step explanation:
I just took the test and i got a one hundred! I really hope it helped!!!!
Hi Mikey
q=3a+5ac
You need to change the equation's side
5ac+3a=q
Factor out a
a(5c+3)=q
Now we need to divide both sides by 5c+3 so we can find the value for a
a(5c+3)/(5c+3)=q/(5c+3)
a= q/(5c+3)
I hope that's help !
(a+b+c)^3=a^3 +b^3+c^3-2(ab+ac+bc)
216=a^3+b^3+c^3-2(11)
a^3+b^3+c^3=238
but ıdk how can ı find -3abc :/
===============================================
Work Shown:
a+b+c = 6
(a+b+c)^2 = 6^2
(a+b+c)(a+b+c) = 36
a(a+b+c)+b(a+b+c)+c(a+b+c) = 36
a^2+ab+ca+ab+b^2+ca+bc+c^2 = 36
a^2+b^2+c^2+2ab+2bc+2ca = 36
a^2+b^2+c^2+2(ab+bc+ca) = 36
a^2+b^2+c^2+2*11 = 36
a^2+b^2+c^2+22 = 36
a^2+b^2+c^2 = 36-22
a^2+b^2+c^2 = 14
-----------------------
a^3+b^3+c^3-3abc = (a+b+c)*(a^2+b^2+c^2 - (ab+bc+ca) )
a^3+b^3+c^3-3abc = 6*(14 - 11)
a^3+b^3+c^3-3abc = 18
c) Decrease 825 by 28%
Please show your working out