Some equations have the form y=kx, where k is a number. Which equation CANNOT be written in the form y=kx?
Some equations have the form y=kx, where k is a - 1

Answers

Answer 1
Answer:

Hello from MrBillDoesMath!

Answer:

y = x - 7

Discussion:

Let's step through the answers one-by-one:

y/6 = x             => multiply both sides by 6

y = 6x

y = kx where k = 6

y/x = 1/2          => multiply both sides by x

y = (1/2) x

y = kx where k = 1/2

y = -0.5x

y = kx where k = -0.5

BUT y = x -7 cannot be written simply as y = kx because of the -7 term.

Thank you,

MrB

Answer 2
Answer:

Answer:

C. y = x - 7

Step-by-step explanation:


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How long is 74% of 60 min
A. 50
B. 35
C.45

Answers

Answer:

Its c

Step-by-step explanation:

Answer:

yes it is C

Step-by-step explanation:

What is the solution to the system of equations below?y=-6x-10
and
y=-3x-21
(2, -22)
(2,48)
(-2, 2)
(-2, -20)

Answers

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equations

y=-6x-10

y=-3x-21

solving the system of the equations

Arrange the equation variables for elimination

\begin{bmatrix}y+6x=-10\n y+3x=-21\end{bmatrix}

y+3x=-21

-

\underline{y+6x=-10}

-3x=-11

\begin{bmatrix}y+6x=-10\n -3x=-11\end{bmatrix}

solve

-3x=-11

Divide both sides by -3

(-3x)/(-3)=(-11)/(-3)

x=(11)/(3)

\mathrm{For\:}y+6x=-10\mathrm{\:plug\:in\:}x=(11)/(3)

y+6\cdot (11)/(3)=-10

y+6\cdot (11)/(3)=-10

y=-32

Therefore, the solutions to the system of the equations are:

y=-32,\:x=(11)/(3)

But, it seems none of the options is true.

Answer:

A. (2, -22)

Step-by-step explanation:

I just took the test and i got a one hundred! I really hope it helped!!!!

the relative frequency of a blue on a spinner is 3/5.how many times would you expect a blue in 250 spins

Answers

250\cdot\frac{3}5=\boxed{150\text{ times}}

Given Q = 3a + 5ac solve for a

Answers

Hi Mikey


q=3a+5ac

You need to change the equation's side

5ac+3a=q

Factor out a

a(5c+3)=q

Now we need to divide both sides by 5c+3 so we can find the value for a

a(5c+3)/(5c+3)=q/(5c+3)

a= q/(5c+3)


I hope that's help !

If a+b+c=6,ab+bc+ca=11,then what is a3+b3+c3-3abc

Answers

(a+b+c)^3=a^3 +b^3+c^3-2(ab+ac+bc)

216=a^3+b^3+c^3-2(11)

a^3+b^3+c^3=238

but ıdk how can ı find -3abc :/

Answer:  18

===============================================

Work Shown:

a+b+c = 6

(a+b+c)^2 = 6^2

(a+b+c)(a+b+c) = 36

a(a+b+c)+b(a+b+c)+c(a+b+c) = 36

a^2+ab+ca+ab+b^2+ca+bc+c^2 = 36

a^2+b^2+c^2+2ab+2bc+2ca = 36

a^2+b^2+c^2+2(ab+bc+ca) = 36

a^2+b^2+c^2+2*11 = 36

a^2+b^2+c^2+22 = 36

a^2+b^2+c^2 = 36-22

a^2+b^2+c^2 = 14

-----------------------

a^3+b^3+c^3-3abc = (a+b+c)*(a^2+b^2+c^2 - (ab+bc+ca) )

a^3+b^3+c^3-3abc = 6*(14 - 11)

a^3+b^3+c^3-3abc = 18

A) Increase 30 by 13%b) Decrease 250 by 15%
c) Decrease 825 by 28%

Please show your working out

Answers

A) multiplier = 1.13
30 x 1.13 = 33.9
B) multiplier = 0.85
250 x 0.8 = 200
C) multiplier = 0.72
825 x 0.72 = 594