Answer:
y = (1/3)x + 7
Step-by-step explanation:
The slope of a line perpendicular to the given line y = -3x - 2 would have to be the negative reciprocal of the slope of the given line:
or, in other words,
the negative reciprocal of -3. That would be +1/3.
Starting with the slope-intercept form of the equation of a straight line, we have:
y = mx + b.
We substitute the coordinates of the given point, (-9,4), and the slope +1/3:
4 = (1/3)(-9) + b.
This simplifies to
4 = -3 + b, from which it can be easily seen that b = 7.
The desired line is y = (1/3)x + 7.
Answer:
1. Simply the left hand side by first multiplying the -12 with the (1-x) to get -12+12x since negative×negative will give you positive. So after the simplification on the left hand side you will get the expression 10-12+12x. Which will give you -2+12x on the left hand side.
2. You do same on the right hand side of the expression 8(-12+6x) -14. So you multiply the 8 with the expression in the bracket ONLY (-12+6x) then afterwards,you add the -14 it to get -96+48x-14 =-110+48x .NOTE. ADDING TO NEGATIVE NUMBERS GIVES YOU A NEGATIVE ANSWER. so -96+(-14)=-110. So after simplification. You will also get the expression-110+48x on the right hand side .
3. Then combining the two sides of the equation, the whole expression becomes
-2+12x = -110+48x. Then you group like terms by sending all number attached with a variable to the right hand side and non attached variable numbers to the left , given you
-2+110 = 48x-12x . NB .WHEN A POSITIVE NUMBER CROSSES THE EQUAL SIGN IT CHANGES TO NEGATIVE AND VICE VERSA.
4. -2+110 = 108 and 48x -12x =36x
So the final expression becomes 108= 36x
Then you divide both side by 36 ,thus 108÷36=36x÷36
Given you x= 3 as your final answer of the expression, since 108÷ 36= 3. And 36x÷36= x
Answer:
thank you
Step-by-step explanation:
i was confused until you did the answer
Answer:
x = π/2 + πk
Step-by-step explanation:
cot² x csc² x + 2 csc² x − cot² x = 2
Multiply both sides by sin² x:
cot² x + 2 − cos² x = 2 sin² x
Add cos² x to both sides:
cot² x + 2 = 2 sin² x + cos² x
Pythagorean identity:
cot² x + 2 = sin² x + 1
Subtract 1 from both sides:
cot² x + 1 = sin² x
Pythagorean identity:
csc² x = sin² x
Multiply both sides by sin² x:
1 = sin⁴ x
Take the fourth root:
sin x = ±1
Solve for x:
x = π/2 + 2πk, 3π/2 + 2πk
Which simplifies to:
x = π/2 + πk
PLEASE HELP