Multiply and simplify: y(2x+3y)(2x+3y)

Answers

Answer 1
Answer: Simplifying y(2x + 3y)(2x + 3y)

Multiply (2x + 3y) * (2x + 3y) y(2x * (2x + 3y) + 3y * (2x + 3y)) y((2x * 2x + 3y * 2x) + 3y * (2x + 3y))
 
Reorder the terms: y((6xy + 4x2) + 3y * (2x + 3y)) y((6xy + 4x2) + 3y * (2x + 3y)) y(6xy + 4x2 + (2x * 3y + 3y * 3y)) y(6xy + 4x2 + (6xy + 9y2))

Reorder the terms: y(6xy + 6xy + 4x2 + 9y2)
 
Combine like terms: 6xy + 6xy = 12xy y(12xy + 4x2 + 9y2) (12xy * y + 4x2 * y + 9y2 * y) (12xy2 + 4x2y + 9y3)
Answer 2
Answer: 2xy+3y^2*2xy+3y^2
3y^2 * 3y^2

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Find the distance between each pair of points (1,2), (-2,2)

Answers

Hi!

So let's imagine a coordinate plane in our head. Imagine where these points are. (1,2) is in quadrant I. (-2,2) is in quadrant II.
They have the same y values, so we just need to know the distance between the x values. We can find that by subtracting.

1-(-2)=3

The distance between (1,2) and (-2,2) is 3.

Hope this helps! :)
-Peredhel

On a coordinate plane, 1,2 and -2,2 would be 3 units apart.

you choose a movie CD at random from a case containing 8 comedy CD's, 5 science fiction, and 7 adventure. The CD is not a comedy

Answers

the answer is 12/20..............
your answer will be 12/20

What is the value of x in the problem -1\2x + 2=3

Answers

-1/2x + 2 = 3
(move the 2 to the other side of the equal sign, change the sign)
-1/2x = 3 - 2
-1/2x = 1
(swap them to make x positive)
-1 = 1/2x
-1 = 0.5x
(divide both sides by 0.5 to have x alone)
-2 = x

Therefore, x = -2.
It is -2. X= -2 (I really need to answer more questions to ask more)

Find the greatest common factor of
21
and
49
.

Answers

The greatest common factor (GCF) is 7.

What is the least common multiple (LCM) of 5 and 7?

Answers

Answer:

35

Step-by-step explanation:

Express each number in terms of its prime factors

5 = 5 and 7 = 7

Then multiply each factor the greatest number of times it occurs in either number.

Both factors occur only once, thus

LCM = 5 × 7 = 35

Answer: 35.

7: 7, 14, 21, 28,35

5: 5, 10, 15,20, 25, 30, 35

In triangle PQR, PR = 23mm, QR = 39mm, and m<R = 163 degrees. Find the area of the triangle to the nearest tenth.

Answers

Answer: 131.1287 square mm (approx)

Step-by-step explanation:

The area of a triangle,

A=(1)/(2) * s_1* s_2* sin \theta

Where s_1 and s_2 are adjacent sides and \theta is the include angle of these sides,

Here PR and QR are adjacent sides and ∠R is the included angle of these sides,

Thus, we can write,

s_1 = PR= 23\text{ mm}, s_2=QR=39\text{ mm} and \theta = 163^(\circ),

Thus, the area of the triangle PQR,

A=(1)/(2) * 23* 39* sin163^(\circ)

A=(262.257419136)/(2) = 131.128709568\approx 131.1287\text{ square mm}