Which system of equations can be used to solve the following problem? Each child ticket for a ride costs $2, while each adult ticket costs $6. If the ride collected a total of $148, and 38 tickets were sold, how many of each type of ticket were sold? Let c be the number of child tickets and a be the number of adult tickets.

A.
Equation set including begin equation begin product of two and c end product plus begin product of six and a end product equals thirty-eight end equation. Begin equation a plus c equals one hundred and forty-eight end equation.

B.
Equation set including begin equation begin product of two and a end product plus begin product of six and c end product equals thirty eight end equation. Begin equation a plus c equals one hundred and forty-eight end equation.

C.
Equation set including begin equation begin product of six and c end product plus begin product of two and a end product equals one hundred and forty-eight end equation. Begin equation c plus a equals thirty-eight end equation.

D.
Equation set including begin equation begin product of two and c end product plus begin product of six and a end product equals one hundred and forty-eight end equation. Begin equation a plus c equals thirty-eight end equation.

Answers

Answer 1

Answer: a.2c+6a=148 a+c=38

this is the answer

Answer 2

Answer: The two equations will be:
$2c+6a=148$
$a+c=38$

The choice appears to be 'D' but the way you have written the equations is very hard to read. Please write them out properly in order to check.

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The measure of the supplement angle is fourteen times greater than its supplement

How to do this two step equation
6a-11=13

Answers

First you add 11 to both sides
6a-11=13
+11 +11

So you get:

6a=24
Next divide both sides by 6
6a=24
6 6

A=4

Solve for x: 7(x - 2) = 5(x + 4)

Answers

Answer:

7(x-2)=5(x+4)

7x-14=5x+20

7x-5x=20+14

2x=34

x=17

7(x - 2) = 5(x + 4)

Multiply the first bracket by 7

(7)(x)=7x

(7)(-2)=-14

Multiply the second bracket by 5

(5)(x)=5x

(5)(4)=20

7x-14=5x+20

Move 5x to the other side. Sign changes from -5x to +5x.

7x-5x-14=5x-5x+20

7x-5x-14=20

2x-14=20

2x-14+14=20+14

2x=34

Divide both sides by 2

2x/2=34/2

Answer: x=17

How many zeros should have 5 to have 72 dividers?

Answers

Hello,

nice as problem.

Here x has a power of 5 as divider and a power of 2 as divider (in order to make a power of 10.

$5=5^1*2^0$

$50=5^1*(5^1*2^1)=5^2*2^1$

$500=5^1*(5^2*2^2)=5^3*2^2$

$50 000 000=5^8*2^7$

Numbers of dividers: (8+1)*(7+1)=9*8=72

If x= root 7+ root 6 /root 7-root 6 then find the value of (x+1/x)

Answers

Answer:

$\huge\boxed{x+(1)/(x)=(13+2√(42))+(13-2√(42))=26}$

Step-by-step explanation:

$x=(\sqrt7+\sqrt6)/(\sqrt7-\sqrt6)\cdot(\sqrt7+\sqrt6)/(\sqrt7+\sqrt6)=((\sqrt7+\sqrt6)^2)/((\sqrt7-\sqrt6)(\sqrt6+\sqrt7))\n\n\n\text{use}\ (a+b)^2=a^2+2ab+b^2\ \text{and}\ (a-b)(a+b)=a^2-b^2$

$x=((\sqrt7)^2+(2)(\sqrt7)(\sqrt6)+(\sqrt6)^2)/((\sqrt7)^2-(\sqrt6)^2)\n\n\n\text{use}\ (√(a))^2=a,\ \text{for}\ a\geq0\n\n\nx=(7+2√(42)+6)/(7-6)=(13+2√(42))/(1)=13+2√(42)\n\n(1)/(x)=(1)/(13+2√(42))\cdot(13-2√(42))/(13-2√(42))=(13-2√(42))/(13^2-(2√(42))^2)=(13-2√(42))/(169-168)\n\n(1)/(x)=13-2√(42)$

Sam wants to enlarge a triangle with sides 3, 6 and 6 inches. If the shortest side of the new triangle is 13 inches, how long will the other sides be?

Answers

The dimension of the dilated triangle will be 13 inches, 26 inches, and 26 inches, respectively.

What is dilation?

Dilation is the process of increasing the size of an item without affecting its form. Depending on the scale factor, the object's size can be raised or lowered. There is no effect of dilation on the angle.

Sam needs to expand a triangle with sides 3, 6, and 6 inches. Assuming that the briefest side of the new triangle is 13 inches. Then the scale factor is given as,

Scale factor = 13 / 3

Then the other dimensions of the triangle will be given as,

⇒ (13 / 3) x 6

⇒ 13 x 2

⇒ 26 inches

The element of the expandedtriangle will be 13 inches, 26 inches, and 26 inches, separately.

More about the dilation link is given below.

brainly.com/question/2856466

#SPJ5

the other sides will be 16 inches long, because 13-3=10, and 10+6=16

PLEASE HELP!! In a recent student government election, the ratio of students who voted for the winner to all the students who voted was 0.88. The number of students who voted was 125. How many votes did the winner get?

Answers

Well,

The the ratio of (number of students who voted for the winner) to (total number of students who voted) is 0.88:1.00 (note that .88 (or 88%) represents the number of students who voted for the winner.

We can re-write the decimal as a percent.
88% of the students voted for the winner.

The total number of students who voted was 125. Therefore (.88)125 = number of students who voted for the winner.

(.88)125 = 110

The winner of the election got 110 votes.

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