B. A crayon melting on a hot sidewalk.
C. Beach sand getting warmed by the sun.
D. An egg getting cooked in a pot of boiling water.
(B) exhaust
(C) oil filter
(D) tires
Answer:
Tires.
Explanation:
There are the few steps which are discussed below should be taken to increase or extend the life of tires.
(1) Avoid fast starts: Fast start of the vehicle will increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.
(2) Avoid fast stop: Fast stop of the vehicle will also increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.
(3) Avoid sharp turns: The alignment of the wheels and tires are in such a way that they work properly when vehicle is drive in a straight path but sharp turn will increase the uneven pressure on the tires will lead to decrease the life of tires.
Therefore, the life of tires can be extend by avoiding all the above mention actions such as fast stop, start and sharp turns.
The life of tires can be extended by avoiding fast starts, stops and sharp turns. These maneuvers cause excessive friction which leads to quicker deterioration. Suitable driving habits can extend the life of the tires.
You can extend the life of your tires by avoiding fast starts, stops, and sharp turns. When a driver performs a fast start, a large amount of friction is produced between the tires and the road, causing the tires to wear faster. The same goes for abrupt stops and sharp turns, which also produce an excess amount of friction, leading to a quicker deterioration of the tires.
Therefore, to extend the life of your tires, it is advisable to drive in a cautious and considerate manner, avoiding fast starts and stops and refraining from making sharp turns whenever possible.
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B.the amount of space that matter ocupies
C.how fast the particles are moving
D.amount of massin a certain place
Any motion in a curved path represents accelerated motion, and requires a force directed toward the center of curvature of the path. This force is called the centripetal force which means "center seeking" force. The force has the magnitude
F = mv^2 / r
Where f is the centripetal force
M is the mass
V is the velocity
R is the radius
19 N = m ( 0.54 m/s)^2 / 0.36 m
Solving for m
M = 23.5 kg
Answer:
23
Explanation: