dessert choices: a cake or a shake, each available in vanilla or strawberry flavors
Answer:
The first answer is the correct choice.
Step-by-step explanation:
For this, there are two initial options. A cake or a shake. This means that there are two different trees that need to exist. One for Cakes and one for shakes.
Each of these trees needs to have the options of having vanilla and strawberry.
The first answer is the only one that follows this criteria
Answer:
1st one is correct.
Step-by-step explanation:
B. 1/2
C. -2
D. -1/2
The graph crosses the x-axis at x = 2 and x = -1 and touches the x-axis at x = 0.
The graph touches the x-axis at x = 2 and x = -1 and crosses the x-axis at x = 0.
The graph crosses the x-axis at x = -2 and x = 1 and touches the x-axis at x = 0.
O The graph touches the x-axis at x = -2 and x = 1 and crosses the x-axis at x = 0.
The correct option is,
⇒ The graph crosses the x-axis at x = -2 and x = 1 and touches the x-axis at x = 0.
A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).
Given function is,
f(x) = x⁴ + x³ - 2x²
Now, We can simplify as;
f(x) = x⁴ + x³ - 2x²
= x²(x² + x - 2)
= x²(x² + 2x - x - 2)
= x²[x(x + 2) - 1(x + 2)]
= x²(x + 2)(x - 1)
So the factored form of the polynomial function is,
f(x) = x²(x + 2)(x - 1)
For x - intercepts,
F(x) = x²(x + 2)(x - 1) = 0
x = -2, 1
This function has even multiplicity = 2 at x = 0.
Therefore, graph of the function will touch the x-axis at x = 0
And at other roots x = -2, 1 has odd multiplicity = 1, so the graph will cross the x-axis.
Thus, Option (3) will be the correct option.
Learn more about the function visit:
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Answer: C. The graph crosses the x-axis at x=-2 and x=1 & touches the x-axis at x=0
Step-by-step explanation:
You can tell this by factoring the equation to get the zeros. To start, pull out the greatest common factor.
f(x) = x^4 + x^3 - 2x^2
Since each term has at least x^2, we can factor it out.
f(x) = x^2(x^2 + x - 2)
Now we can factor the inside by looking for factors of the constant, which is 2, that add up to the coefficient of x. 2 and -1 both add up to 1 and multiply to -2. So, we place these two numbers in parenthesis with an x.
f(x) = x^2(x + 2)(x - 1)
Now we can also separate the x^2 into 2 x's.
f(x) = (x)(x)(x + 2)(x - 1)
To find the zeros, we need to set them all equal to 0
x = 0
x = 0
x + 2 = 0
x = -2
x - 1 = 0
x = 1
Since there are two 0's, we know the graph just touches there. Since there are 1 of the other two numbers, we know that it crosses there.
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6
yard long,
1
_
4
yard long,
and
2
_
3
yard long. He needs at least 1 yard of cable.
a
Which two pieces together make a length at least
1 yard and closest to 1 yard?
b
If Carl uses the two shortest pieces, how much more cable would he need?