Sarah and her three friends are decorating picture frames with ribbon. They have 3 rolls of ribbon to share evenly. How does this situation represent division?

Answers

Answer 1

Answer: Let's see here. Sarah is one person. Her three friends are three more. That means 4 people are decorating picture frames. However, we only have 3 rolls of ribbon! We can give an entire roll to each person, but one person would have no roll to decorate with! What do we do? We have to divide this. By definition, divide means to separate something(in this case, ribbon rolls) into (equal) parts. So, we must divide them so everyone gets an EQUAL ribbon roll length.

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How do you find the surface area of a regular pyramid

Answers

The surface area of the pyramid is calculated by the formula B +(1/2) *P*L.

What is a Regular Pyramid?

A regular pyramid is a three dimensional structure with a regular polygon base and all the lateral surfaces are equal.

The surface area of a Regular Pyramid is the sum of the area of the base and the area of the lateral surface.

Surface area of Pyramid = Area of base + Lateral surface area of the sides

Surface area of Regular Pyramid = B +(1/2) *P*L

Here P is the perimeter of the base and L is the slant height, B is the area of the base.

Therefore, the surface area of the pyramid is calculated by the formula B +(1/2) *P*L.

To know more about Regular Pyramid

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The lateral surface area of a regular pyramid is the sum of the areas of its lateral faces. The total surface area of a regular pyramid is the sum of the areas of its lateral faces and its base. The general formula for the lateral surface area of a regular pyramid is where p represents the perimeter of the base and l the slant height. Example 1:Find the lateral surface area of a regular pyramid with a triangular base if each edge of the base measures 8 inches and the slant height is 5 inches.The perimeter of the base is the sum of the sides.p = 3(8) = 24 inchesThe general formula for the total surface area of a regular pyramid is where p represents the perimeter of the base, l the slant height and B the area of the base. Example 2:Find the total surface area of a regular pyramid with a square base if each edge of the base measures 16 inches, the slant height of a side is 17 inches and the altitude is 15 inches.The perimeter of the base is 4s since it is a square.p = 4(16) = 64 inches The area of the base is s2.B = 162 = 256 inches2T. S. A. = There is no formula for a surface area of a non-regular pyramid since slant height is not defined. To find the area, find the area of each face and the area of the base and add them.

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What is 2/3 divided by 5/3

Answers

Answer:

2/5

Step-by-step explanation:

Step 1:

2/3 ÷ 5/3 Equation

Step 2:

2/3 × 3/5 Reciprocal

Answer:

2/5 Multiply

Hope This Helps :)

What are the solutions to the equation? x2 + 6x = 40

Answers

x² + 6x = 40

Subtract 40 from both sides:

x² + 6x - 40 = 40 - 40

refine: x² + 6x - 40 = 0

factor x² + 6x - 40 = 0

( x- 4 ) ( x + 10 ) = 0

solve x - 4 = 0

x = 0 + 4

x = 4

solve x + 10 = 0

x = 0 - 10

x = - 10

solution : x = 4 , x = - 10

hope this helps!

Answer:

$x_1= 4\nx_2=-10$

Step-by-step explanation:

$x^2+6x=40$

Since it is an equation squared to find the two values of x we can apply the formula of the solver

$x = \frac {-b \pm \sqrt {b^2 - 4ac}}{2a}$

we equate the equation to zero to be able to apply the solver

$x^2+6x=40\nx^2+6x-40=0$

$a=1 \nb=6\nc=-40$

$x = \frac {-6 \pm \sqrt {(6)^2 - 4(1)(-40)}}{2(1)}\nx = \frac {-6 \pm \sqrt {36+160}}{2}\nx = \frac {-6 \pm \sqrt {196}}{2}\nx = \frac {-6 \pm \ 14}{2}\nx_1= \frac {-6 +\ 14}{2}\nx_1= (8)/(2)= 4\nx_2=\frac {-6 - 14}{2}\nx_2=(-20)/(2)= -10$

$x_1= 4\nx_2=-10$

Which of the following is an infinite set?the set of lessons in this course
the set of even numbers from 0 to 10
10 billion
the set of integers
the null set
none of the above

Answers

The set of integers is an infinitive set, whereas the other options are not infinite.

Reorder the steps to construct Angle JOB, a copy of Angle A.__ Construct oj
__ Place your compass point at the vertex of Angle A. Create an arc that intersects both rays of Angle A.
__ On Angle A, set your compass point on the intersection of the arc and ray and the pencil on the other intersection of the arc and second ray. Lock your compass.
__ Place the point of the compass on the intersection of the arc on OB. Mark an arc through the large arc created in a previous step. Label the point of intersection of the two arcs point J.
__ Draw a ray that will become one of the two rays of the new angle. Label the ray OB.
__ Without changing your compass setting, create an arc from point O that intersects OB. Be sure to make a large arc.

Answers

Answer:

The right order is given as follows;

_Draw a ray that will become one of the two rays of the new angle, label OB

_Place your compass point at the vertex of Angle A. Create an arc that intersects both rays of Angle A

_On Angle A, set the compass point on the intersection of the arc and ray and the pencil on the other intersection of the arc and second ray. Lock your compass

_Without changing your compass setting, create an arc from point O that intersects OB. Be sure to make a large arc.

_Place the point of the compass on the intersection of the arc on OB. Mark an arc arc through the large arc created in a previous step. Label the point of intersection of the two arcs point J.

_Construct OJ

Step-by-step explanation:

1) The first step is to draw a line in the location where the angle to be copied is to be constructed

2) The distance of two points on the rays forming the angle to be copied from the vertex are found by drawing an arc from the vertex and setting the compass opening width to the distances between the intersection of the arc and the rays

3) With the set compass width from the step above, an arc is drawn which intersects the constructed first new ray. The arc is made to extend to a large angle to accommodate large angle sizes

4) From the point of intersection of the arc on the new line, another arc is drawn to intersect the previous arc located on the new line construction

5) Join the point intersection of the two arcs on the new construction to the start point of the constructed first new line (the point from which the first arc was constructed to complete the construction of a copy of the angle.

Final answer:

To construct Angle JOB, a copy of Angle A, follow these steps: 1. Create an arc that intersects both rays of Angle A. 2. Set your compass point on the intersection of the arc and ray, and the pencil on the other intersection of the arc and second ray. Lock your compass. 3. Create an arc from point O that intersects OB, and label the point of intersection as point J. 4. Draw a ray OB. 5. Place the point of the compass on the intersection of the arc on OB and mark an arc through the large arc created in a previous step. 6. Finally, construct oj.

Explanation:

Place your compass point at the vertex of Angle A. Create an arc that intersects both rays of Angle A.
On Angle A, set your compass point on the intersection of the arc and ray and the pencil on the other intersection of the arc and second ray. Lock your compass.
Without changing your compass setting, create an arc from point O that intersects OB. Be sure to make a large arc. Label the point of intersection of the two arcs point J.
Draw a ray that will become one of the two rays of the new angle. Label the ray OB.
Place the point of the compass at the intersection of the arc on OB. Mark an arc through the large arc created in the previous step.
Construct oj

Learn more about Geometry Construction here:

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The sum of four consecutive odd integers is 328. What are the integers? (show your work)