Answer:
no they are not because 2/3 is equal to .6 and 5/6 is equal to .83
Step-by-step explanation:
Side lengths: RS=7 and ST=7, and angle=90 degrees
Why?
Since second coordinates of R and S are the same so we can just count the length by adding first coordinate of R and first coordinate of S= |-3|+4=7
Since first coordinates of R is the same as first coordinate of T so we can just count the length by adding second coordinates of S and T=5+|-2|=7
Angle: RST is =90 degrees because triangle RST is right angled triangle. Why? Because RS is parallel to X axis(the same second coordinates of R and S) and ST is parallel to Y axis(the same coordinates of S and T) .
Winter Olympics. If the mean is 20.4 and the standard deviation is 7.9, circle all values that
fall within one standard deviation of the mean.
6, 11, 15, 17, 19, 24, 25, 26, 28, 33
Answer:
You should circle:
15, 17, 19, 24, 25, 26, 28
Step-by-step explanation:
The values x that falls within 1 standard deviation of the mean are those which.
6
|6 - 20.4| = 14.4 > 7.9
6 is not within 1 standard deviation of the mean.
11
|11 - 20.4| = 9.4 > 7.9
11 is not within 1 standard deviation of the mean.
15
|15 - 20.4| = 5.4 < 7.9
15 is within 1 standard deviation of the mean.
17
|17 - 20.4| = 3.4 < 7.9
17 is within 1 standard deviation of the mean.
19
|19 - 20.4| = 1.4 < 7.9
19 is within 1 standard deviation of the mean.
24
|24 - 20.4| = 3.6 < 7.9
24 is within 1 standard deviation of the mean.
25
|25 - 20.4| = 4.6 < 7.9
25 is within 1 standard deviation of the mean.
26
|26 - 20.4| = 5.6 < 7.9
26 is within 1 standard deviation of the mean.
28
|28 - 20.4| = 7.6 < 7.9
28 is within 1 standard deviation of the mean.
33
|33 - 20.4| = 12.6 > 7.9
33 is not within 1 standard deviation of the mean.
Answer:
If x is an integer, then for values of x ≤ 0 would -x be positive.
General Formulas and Concepts:
Math
Step-by-step explanation:
We know that integers comprise of the number line from -∞ to ∞. We can have numbers like -3, -2, -1, 0, 1, 2 ,3.
If we say that x is an integer, and that -x must be positive, then that means the integer x must be negative, because a negative times a negative is a positive.
∴ x can only be negative integers, thus giving us x ≤ 0.
A. factoring
B. isolating the x^2 term and finding the square root of both sides
C. using the quadratic formula
D. all three methods would be efficient
Quadratic equation is the polynomial equation whose highest power of the variable is two. The standard form of the given equation is,
The factor roots of the equation are -2 and 8.
The quadratic equation given in the problem is,
Quadratic equation is the polynomial equation whose highest power of the variable is two. Quadratic equation is the equation which involves only one unknown variable.
The standard form of the quadratic equitation can be given as,
Here, a,b and c are the known variables and x is the unknown.
Convert the given equation in the standard form,
Equate the above equation to the zero and bring all the variables and constant one side,
Arrange the equation with the power of x,
Factored the above equation,
equate them to the zero we get,
Hence the standard form of the given equation is,
The factor roots of the equation are -2 and 8.
Learn more about the quadratic equation here;
Answer:
(x-18) (x+2) =0
and
x=-2 or x=18