Find the point where two lines intersct

Answers

Answer 1
Answer: y=2x+3
y=-x
the interssection is the set of points that make both systems true

set them eual to each other since they both equal y
2x+3=y=-x
2x+3=-x
add x to both sides
3x+3=0
subtract 3
3x=-3
divid 3
x=-1

subsitue
y=-x
y=-(-1)
y=1


(x,y)
the intersection is (-1,1)
Answer 2
Answer: y=2x+3
y=-x
To find the point, first set them equal to each other:
2x+3=-x
Then, solve for x:
3x=-3
x = -1
y = -x --> y = -(-1) = 1
So the point is (-1,1)

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Which equations have a negative solution?Choose all answers that are correct.

A. -w/2=11
B. -1/6x=-3
C.-4=v/(-10)
D. -3/4 2=8

Answers

A. w= -22 so A has a negative solution.D doesn't have a variable so I'm not sure about it (did you type it correctly?), but because only one side of the equation has a negative number, I'm guessing D is also a negative solution

The answer is A and D :)))))))))

What is the sum or difference of 517 37/50 + 312 3/100

Answers

the sum is 829.77, and the difference is 205.44

Solve for X and Y 3x+(2 x-y)i = 6-3i

Answers

Answer:

x = 2 and y = 7

Step-by-step explanation:

\text{Two complex numbers are equal when they have equal real parts}\n\text{ and equal imaginary parts}\n\na+bi=c+di\iff a=c\ and\ b=d

3x+(2x-y)i=6-3i\iff3x=6\ \wedge\ 2x-y=-3\n\n3x=6\qquad\text{divide both sides by 3}\n\n\boxed{x=2}\n\n\text{Put the value of x to the second equation:}\n\n2(2)-y=-3\n\n4-y=-3\qquad\text{subtract 4 from both sides}\n\n-y=-7\qquad\text{change the signs}\n\n\boxed{y=7}

A circular tabletop is to be cut from a rectangular pieceof wood that measures 1.20 m by 1.80 m.
What is the radius of the largest tabletop that could be cut?
Justify your answer. Include a sketch​

Answers

The radius of the tabletop is the distance from the center to its circumference

The largest radius of the circular tabletop is 0.6 meters

The dimension of the rectangular piece of wood is given as:

Length = 1.20 m

Width = 1.80 m

From the given dimension, we have the following observation:

The length of the rectangular piece is smaller than its width.

This means that:

\mathbf{Diameter = Length}

Substitute 1.20 m for Length

\mathbf{Diameter = 1.20 m}

Divide both sides of the equation by 2 to calculate the radius

\mathbf{\frac{Diameter}2 = (1.20 m)/(2)}

Simplify

\mathbf{Radius = 0.60 m}

Hence, the largest radius of the tabletop is 0.6 meters

Read more about radius at:

brainly.com/question/1486933

the radius of the largest tabletop that could be cut is 0.6 m .

Step-by-step explanation:

Here we have , A circular tabletop is to be cut from a rectangular piece of wood that measures 1.20 m by 1.80 m. We need to find What is the radius of the largest tabletop that could be cut. Let's find out:

We know that For a circle to be completely inscribed in a rectangle , It's diameter must be equal to it's Length . Now , According to question we have following parameters as :

Length = 1.2\nBreadth=1.8

So , Diameter of circle :

Diameter = Length = 1.2m

Now , We know that

Diameter =2(radius)  = 1.2m

radius = (1.2)/(2)

radius =0.6m

Therefore ,  the radius of the largest tabletop that could be cut is 0.6 m .

The house has five doors. the number of windows is two more than 5. how are there?

Answers

more than in mathematics means addition

So if there are 5 doors, and there are two more windows than doors, then there is 5 + 2 = 7 windows.

So, there is a total of 7 windows.

I need help with this Algebra 1 Study Guide. It has 5 questions . This has many hard questions so to you people that like a challenge, can you help me out?

Answers

1. Rational numbers can be written as a ratio (fraction)
Whole numbers are rational. 5 = 5/1, for example.
Square roots are NOT rational.  Example: √3
However, square roots of square numbers can be simplified, and are therefore rational. √4 = 2, rational.

√4 + √16 = 2 + 4 = 6. rational
√5 + √36... irrational
√9 + √24... irrational
2 × √4 = 2 × 2 = 4. rational
√49 × √81 = 7 × 9 = 63. rational
3√12... irrational

2. n^\frac12=\sqrtn
9^\frac32=9^3*\frac12=√(9^3)=√(729)=29

3. (n^a)/(n^b)=n^(a-b)

(a^\frac13)/(a^\frac14)=a^(\frac13-\frac14)=a^{(1)/(12)}

4. n^\frac1x=\sqrt[x]n

\sqrt[3]{m^2n^5}=m^(\frac23)n^(\frac53)

5. √(a)*√(b)=√(ab)

√(3)*√(12)=√(3*12)=√(36)=6

A, since neither 3 nor 12 is a square but we end up with 6.