Factorise p^-6p+8
Explanation would be helpful too. Thank you so much.
Answers
Answer 1
Answer:
assuming you meant
p^2-6p+8
then
find what 2 numbes multiply to get 8 and add to get -6
numbers are -2 and -4
(p-2)(p-4)
p^2-6p+8
then
find what 2 numbes multiply to get 8 and add to get -6
numbers are -2 and -4
(p-2)(p-4)
Answer 2
Answer:
(p-4)(p-2)
The 2 numbers have to add up to make the -6
-2+-4=-6
and they have to multiply together to make 8
-2 x -4 = 8
hope this helps!
The 2 numbers have to add up to make the -6
-2+-4=-6
and they have to multiply together to make 8
-2 x -4 = 8
hope this helps!
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5( 3u - 4) + 615u - 20 + 6....Hope I'm right !!!
Answers
15. (2•l)+(2•w)=38.
(2•l)+8=38.
Subtract 8 from both sides which leaves (2•l)=30.
Divide by 2 from both sides and that leaves 15.
(2•l)+8=38.
Subtract 8 from both sides which leaves (2•l)=30.
Divide by 2 from both sides and that leaves 15.
Answers
p=number of pens
h=number of highlighters
p+h=8
1.09h+0.69p=752
p+h=8
minus h from both sides
p=8-h
sub that for p
1.09h+0.69(8-h)=7.52
1.09h+5.52-0.69h=7.52
0.4h+5.52=7.52
minus 5.52 from both sides
0.4h=2
divide both sides by 0.4
h=5
sub back
h=8-p
5=8-p
minus 8 frm both sides
-3=-p
mltiply both sides by -1
3=p
3 pens you bought
h=number of highlighters
p+h=8
1.09h+0.69p=752
p+h=8
minus h from both sides
p=8-h
sub that for p
1.09h+0.69(8-h)=7.52
1.09h+5.52-0.69h=7.52
0.4h+5.52=7.52
minus 5.52 from both sides
0.4h=2
divide both sides by 0.4
h=5
sub back
h=8-p
5=8-p
minus 8 frm both sides
-3=-p
mltiply both sides by -1
3=p
3 pens you bought
Let p be the number of pens purchased and h be the number of highlighters purchased.
p + h = 8 ..........(1)
h = 8 - p ...........(2)
0.69p + 1.09h = 7.52 ........(3)
Plugging the value for h from (2) into equation (3) we get:
0.69p + 1.09(8 - p) = 7.52 .....(4)
Expanding the bracket in (4) gives:
0.69p + 8.72 - 1.09p = 7.52
Therefore
-0.4p = -1.2
p = -1.2/-0.4 = 3
The answer is 3 pens.
p + h = 8 ..........(1)
h = 8 - p ...........(2)
0.69p + 1.09h = 7.52 ........(3)
Plugging the value for h from (2) into equation (3) we get:
0.69p + 1.09(8 - p) = 7.52 .....(4)
Expanding the bracket in (4) gives:
0.69p + 8.72 - 1.09p = 7.52
Therefore
-0.4p = -1.2
p = -1.2/-0.4 = 3
The answer is 3 pens.
Answers
A fraction is undefined if its denominator is zero, because then it's saying
"Division by zero !" which is a definite no-no.
Can the denominator of the fraction in #5 ever be zero ?
The denominator is a quadratic polynomial. Do you know
how to solve (a quadratic polynomial) = 0 ?
This problem is even easier than that, because it gives you some choices.
So you don't even have to solve the quadratic equation. All you have to do
is check out the choices.
Do you see choice of 'x' values that make the denominator zero ?
Big sloppy hint: Look at choice-E very very carefully.
Is that enough help ?
"Division by zero !" which is a definite no-no.
Can the denominator of the fraction in #5 ever be zero ?
The denominator is a quadratic polynomial. Do you know
how to solve (a quadratic polynomial) = 0 ?
This problem is even easier than that, because it gives you some choices.
So you don't even have to solve the quadratic equation. All you have to do
is check out the choices.
Do you see choice of 'x' values that make the denominator zero ?
Big sloppy hint: Look at choice-E very very carefully.
Is that enough help ?
Explain when is a rational expression restricted.
Answers
restricted values are when you get things that aren't allowed
the 2 main ones are
1.having a negative result under the squaer root sign
2. dividing by zero
example
√(x-3)=y
x cannot be any number less than 3
example the equation 3/x, 0 is a restricted value for x
3/(x+2), -2 is a restricted value for x
the 2 main ones are
1.having a negative result under the squaer root sign
2. dividing by zero
example
√(x-3)=y
x cannot be any number less than 3
example the equation 3/x, 0 is a restricted value for x
3/(x+2), -2 is a restricted value for x