Answer:
Image attached is your answer.
Step-by-step explanation:
Hope this helps all who have struggled to find the answer.
Which transformation can not be used to prove that ABC is congruent to DEF ?
D
the answer is D. dilation cannot be used to prove this
The answer is D since dialation only beating to increase in size
Answer:
Challenge #1:
Different examples:
2x+1=3x+2
4x+3=5x+4
3x+2=4x+3
Challenge #2:
Different examples:
2x+0=4x+1
3x+1=2x+5
6x+5=8x+6
Answer:
(-2x + 1 = 1x + 1) or (-4x + 2 = 2x + 2)
Step-by-step explanation:
The solution is, the 8th term of the arithmetic sequence with a first term of 7 and a common difference of -3 is, a_8 = - 14.
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
For instance, the sequence 5, 7, 9, 11, 13, 15.. . is an arithmetic progression with a common difference of 2.
The nth term of AP : a_n = a + (n – 1) × d
here, we have,
we know that,
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 7 and d = - 3,
thus,
a_8 = 7 + (7 × - 3) = 7 - 21 = - 14
Hence, The solution is, the 8th term of the arithmetic sequence with a first term of 7 and a common difference of -3 is, a_8 = - 14.
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Answer:
= - 14
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 7 and d = - 3, thus
= 7 + (7 × - 3) = 7 - 21 = - 14