MATHEMATICS HIGH SCHOOL

What is the length of s?​
What is the length of s?​ - 1

Answers

Answer 1
Answer:

Answer:

20.78460969 = s

Step-by-step explanation:

tan theta = opposite side / adjacent side

tan 60 = s /12

Multiply each side by 12

12 tan 60 = s /12 *12

20.78460969 = s

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Find the midpoint of the line segment whose endpoints are (-2, 5) and (4, -9).

What is the parallel to the line x=15 and contains the point (-1,5)

Answers

Look\ at\ the\ picture.\n\nx=-1\ is\ parallel\ to\ the\ x=15\ and\ contains\ the\ point\ (-1;\ 5)
The line x=15 is the line parallel to the axis OY.
So the paralel lines to the line x=15 are  parallel  to the axis OY, so their equations are  x=a,  where "a"  is a real number. 
Here you've got point (-1,5) so x-coordinate is x=-1, 
So equation this line  is x=-1
....

F(c)= 9/5c+ 32 I just don't understand how to find the inverse of the function

Answers

F = 9/5 C + 32
- 32 -32

subtracting - 32 from both sides

F - 32 = 9/5c
5/9 F -32 = 5/9(9/5)C

Invert 9/5 to 5/9 multiply to both sides

5/9F - 32 = C

The answer is 5/9F-32 = C

A bar graph is used to represent numerical data.

true or false

Answers

A bar graph is used to represent numerical data.true or false correct answer:true

Answer:

the correct answer is true. easy

. If B is a complement of A, and C is a supplement of B, find these measures. A
equals 40

Answers

complementary angles add up to 90
so if A and B are complementary....and A = 40, then B = 90 - 40 = 50.

supplementary angles add up to 180
so if B and C are supplementary, and B = 50, then C = 180 - 50 = 130

3. Length of a cubic container is 20 cm .A cube with a length of edges 5 cm will be used to take some water from a water barrel. Determine the maximum number of cubes that need to use to fill the container with water.​

Answers

We have l = 20 * 20 * 20 = 8000 cm3

One cube will have l = 5 * 5 * 5 = 125 cm3

-> The maximum number of cubes that need to use to fill the container with water is 8000 / 125 = 64

Find the simplified form of each expression (-2)^-5
(-8.3)^0
-(10)^-1
1/a^-2

Answers

{ \left( -2 \right) }^( -5 )=\frac { 1 }{ { \left( -2 \right) }^( 5 ) } =-\frac { 1 }{ 32 } \n \n { \left( -8.3 \right) }^( 0 )=1\n \n -{ 10 }^( -1 )=-\frac { 1 }{ { 10 }^( 1 ) } =-\frac { 1 }{ 10 } \n \n \frac { 1 }{ { a }^( -2 ) } =\frac { 1 }{ \frac { 1 }{ { a }^( 2 ) } } =\frac { 1 }{ 1 } / \frac { 1 }{ { a }^( 2 ) } =\frac { 1 }{ 1 } * \frac { { a }^( 2 ) }{ 1 } ={ a }^( 2 )
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