Answer:
perpendicular lines
Step-by-step explanation:
Answer:
Perpendicular lines
Step-by-step explanation:
The slopes are negative reciprocals
for the first equation we get
y=2x+5/2
and the second we get
y=-1/2x-1/10
2 and -1/2 are negative reciprocals
Answer:
66 + 1 ( not fully shaded ) squares will be shaded.
66.67% region will be shaded
Step-by-step explanation:
It is given that Marks uses a grid to model percent equivalent of .
Let us assume that Mark uses a model containing 100 grids.
Now, as the grids are divided into region equivalent to i.e. it is divided into 3 parts.
Moreover, 2 out of those 3 parts will be shaded.
As,
i.e. =66.67%
So, it gives us that 66 squares in the grid will be fully shaded and one will not be fully shaded.
Hence, 66 + 1 ( not fully shaded ) squares will be shaded and in percent, 66.67% of the region will be shaded.
To represent the fraction 2/3 on a grid, approximately 67% of the squares on the grid should be shaded. This means such a fraction corresponds to 67 out of 100 squares on a 100-square grid or equivalently 67% shaded.
To determine how many grid squares Mark should shade to model the percent equivalent of the fraction 2/3, we need to understand the relationship between fractions, decimals, and percents. When we convert the fraction 2/3 into a decimal, we get approximately 0.67. To represent this as a percent, we multiply by 100, which gives us 67%. So, about 67 out of 100 squares should be shaded.
Let's say Mark's grid has 100 squares (10 rows by 10 columns). In that case, he would shade about 67 squares to represent 2/3 as a percent. If the grid contains fewer than 100 squares, he would need to adjust accordingly.
In summary, the model would show about 67% shaded.
#SPJ6
10^2 = 100 and 5^2 = 25
100 and 25 gives you 125. Because, 100 +25 = 125.
An algebraic statement that represents all the ways Eric will wins is , where be the number that Eric thinks and be the number that Nita thinks.
If the difference between their two numbers is less than, then Erik wins. If the difference between their two numbers is greater than, then Nita wins.
Let be the number that Eric thinks and be the number that Nita thinks.
For to Eric to win, the difference in the numbers should be less than.
That is, , for or , for .
Or .
Learn more about inequalities and graph here:
Erik- |x-y|<10
Nita- |x-y|>10
B1/25
c 5/4
d 1