Whats the mean, media, maximum,minimum,mode and range of 1,2,1,3,4

Answers

Answer 1
Answer: First put the numbers in order least to greatest. 
(1,1,2,3,4)
The mean is the average of the group of numbers.
Too find it you add all the numbers up and divide it by how many numbers there are.
In this case it would be 11 divided by 5 so the mean would be 2 (1)/(5)

Median is just another word for middle. After putting the numbers in order, the number in the center of the group is the median, in this case it would be 2.

The maximum would just be the largest number which is self explantory (4)

The minimum would be the lowest number (1)

I was taught to see mode as the word "most". All you do is see which number occurs the most. If all the numbers only occur once, your answer would be "No mode"


It is that simple! The Range is the difference between the lowest and highest number. So all you have to do is subtract the maximum by the minimum. In this case it would be 4-1 = 3


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Solve for b. -9/3 + b = -1

Answers

-(9)/(3) + b = -1
Simplify -(9)/(3), which is: -3
-3 + b = -1
take -3 to the other side
-3 (+3) + b = -1 + (3)
-3 and + 3 cancels out
b = 2

Check:
-(9)/(3) + (2) = -1
-3 + 2 = -1
-1 = -1

Kelly and 23 friends go roller skating.They pay a total of 186 dollars. About how much does it cost  for one person to skate?

Answers

You need to figure out the unit rate so you need to:
1. divide 186 by 23= 8.08695....
2. You only need to figure out the answer to the hundredth of a percent so you would round and get $8.09
3. The answer is $8.09
To do this first you must find the total number of people 23+1=24 so there are 24 people they paid 186 total divide this by 24 and you get 7.75 so each skate cost $7.75

In the past you paid $800 per month to rent your apartment. You now pay $900 per month for your rent. What is the percent increase in your rent?

Answers

Answer:

Percent increase in rent is 12.5%

Step-by-step explanation:

Given:

In past the rent you paid $800 per month to rent your apartment.

i.e, Original rent paid = $ 800

You now pay $900 per month for your rent.

i.e New rent paid = $900

Increase in the rent is= New rent - Original rent= $900 -$800 =$100.

To find the percent increase in rent.

Percent increase is equal to Divide the increase by the original number and multiply the answer by 100.

i.e,

Percent Increase = (Increase in rent)/(Original rent ) * 100

then;

Percent Increase = (\$ 100)/(\$ 800) * 100

Simplify:

Percent Increase = 12.5\%

therefore, the percent increase in your rent is 12.5%

12.5% the difference is $100 write a proportion, 100 = x800 100 differencece = xoriginal 100

Terri's teacher gives her the equation 3(5)^x=127-2x, and tells her that she will not know how to solve it algebraically. Explain how Terri could use a graph to solve the equation, find the value of x to the nearest tenth

Answers

f(x)=3\cdot5^x\ \ \ and\ \ \ g(x)=127-2x\n\nf(x)=g(x)\ \ \ \Leftrightarrow\ \ \ x\approx2.3043\n\nthe\ graph\ in\ annex

How do i find the perimeter of the triangle with vertices at three points (0,1),(2,1), and (0,3)?

Answers

The perimeter is the sum of the lengths of the three sides.

To find the perimeter, you need to find the lengths of the three sides.

For each side, you are given the points at the two ends.You need to find the distance between those two points.

Once you have all thee distances, add them up.

That's how.
Well I'm not just going to tell you the answer, you need to "experience" how you do it. Basically you use the distance formula, which I'll show you in a bit, to fine the length of the segments. Then you just add them up.
\sqrt{ (x_(2)- x_(1)) ^(2) +(y_(2)-y_(1))^(2)

A set of data includes 101 data points ranging from 0 – 200. If the data is split into classes with a range of 20 (1 – 20, 21 – 40, etc), and there are no values that fall in the class 101 – 120, what can you say about the data?A.The mean of the data will not be between 101 and 120.
B. All the data lies below 100.
C. The relative frequency of the class 101 – 120 is 0.
D. The median could be in the range 101 – 120.

Answers

Answer:

The relative frequency of the class 101 – 120 is 0.

Step-by-step explanation:

i took the quiz

D, because there might be values higher than 120, because the data points range from 0 - 200.