BC+A=41
What is A, B, C
For the given system of equations, when B = 2, the values are A = 133 and C = -216. Values will vary with different choices of B.
To solve for the values of A, B, and C in the system of equations:
AB + C = 50
BC + A = 41
We can use a systematic approach. Let's first isolate one variable in one equation and then substitute it into the other equation.
From the first equation (AB + C = 50), we can isolate C:
C = 50 - AB
Now, substitute this expression for C into the second equation:
B(50 - AB) + A = 41
Expand and simplify:
50B - + A = 41
Rearrange terms:
- 50B + A = 41
Now, let's consider this as a quadratic equation in terms of A and solve for A:
A = 41 - + 50B
Now that we have expressions for A and C in terms of B, we can choose a value for B, and then calculate the corresponding values of A and C. For instance, let's say B = 2:
A = 41 - (2)() + 50(2) = 41 - 8 + 100 = 133
C = 50 - (2)(133) = 50 - 266 = -216
So, for B = 2, we have A = 133 and C = -216. You can similarly calculate values for different values of B.
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Complete question below:
What are the values of A, B, and C in the system of equations:
AB + C = 50
BC + A = 41?
The expressionrepresents the number of hours Mrs. Nakos worked during the last week of school. When expression evaluated, it equals 6 hours. So, Mrs. Nakos worked 6 hours that week.
To find the number of hours Mrs. Nakos worked during the last week of school, you can evaluate the expression step by step:
1. Start by evaluating the expression inside the parentheses:
2. Now, you have the expression To calculate this, multiply 12 by
since dividing by 2 is the same as multiplying by
So, Mrs. Nakos worked 6 hours during the last week of school.
The expression represents the number of hours worked, and when evaluated, it equals 6 hours. Therefore, Mrs. Nakos worked 6 hours that week.
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60 pedazos.
15 pedazos.
45 pedazos.
Answer:
30 pedazos
Step-by-step explanation:
(15/2)/(1/4)
= (15*4)/(2*1)
= 60/2
= 30
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