train B leaves Bridgton and heads east at
100 mi/h. At what time will train B catch
up to train A?
Train B will catchup to Train A at 5:30 PM.
We have,
d = distance covered by both trains when they meet
t = time it takes for train B to catch up to train A
For train A:
Distance = Speed × Time
d = 90t
For train B:
Distance = Speed × Time
d = 100(t - 0.5) (train B departs 30 minutes (0.5 hours) later than train A)
Since both equations represent the samedistance, we can set them equal to each other:
90t = 100(t - 0.5)
Let's solve for t:
90t = 100t - 50
10t = 50
t = 5
It will take 5 hours for train B to catchup to train A.
To determine the time when train B catches up to train A, we add the 5 hours to the departure time of train B, which is 12:30 PM:
12:30 PM + 5 hours = 5:30 PM
Therefore,
Train B will catchup to Train A at 5:30 PM.
Learn more about speed here:
#SPJ6
I'd say maybe by 5:30 b would
A.y = –2
B.y = 0
C.y = 2
D.y = 3
2) (2,10)
3) (-2,-10)
4) (1,-5)
54c3d4 + 9c4d2