I need help ASAP.The average time that it takes for the car to travel the first 0.25m is_____

The average time to travel just between 0.25m and 0.50m is_____

Given the time taken to travel the second 0.25m section, the velocity would be____m/s
I need help ASAP. The average time that it takes - 1

Answers

Answer 1
Answer:

1. Average time for the first 0.25 m: 2.23 s

Explanation:

The average time that it takes for the car to travel the first 0.25 m is given by the average of the first three measures, so:

t=(2.24s+2.21s+2.23s)/(3)=2.227 s=2.23 s

2. Average time to travel between 0.25 m and 0.50 m: 0.90 s

Explanation:

First of all, we need to calculate the time the car takes to travel between 0.25 m and 0.50 m for each trial:

t1 = 3.16 s - 2.24 s = 0.92 s

t2 = 3.08 s - 2.21 s = 0.87 s

t3 = 3.15 s - 2.23 s =  0.92 s

So, the average time is

t=(0.92 s + 0.87 s + 0.92 s)/(3)=0.903 s=0.90 s

3. Velocity in the second 0.25 m section: 0.28 m/s

Explanation:

The average velocity in the second 0.25 m section is equal to the ratio between the distance covered (0.25 m) and the average time taken (0.90 s):

v=(d)/(t)=(0.25 m)/(0.90 s)=0.28 m/s

Answer 2
Answer:

Answer:

1. 2.23

2. 0.90

3. 0.28


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A 45.2-kg wagon is towed up a hill inclined at 18.5∘ with respect to the horizontal. The tow rope is parallel to the incline and has a tension of 191 N in it. Assume that the wagon starts from rest at the bottom of the hill, and neglect friction. How fast is the wagon going after moving 83.8 m up the hill?

Answers

Answer:

The speed is 29.9 m/s

Explanation:

The force created from gravity due to the wagon mass is:

F=m*g*sin(18.5)\nF=45.2*9.8*sin(18.5)\nF=140.55

140.55 N pull the wagon down. Two parallel rope with tension of 191N creates 382 N on the wagon. Therefore:

T_(total)=382-140.55=241.45

241.45 N force is pulling up the wagon. Then we need to find the acceleration of the wagon under this force:

F=m*a\n241.45=45.2*a\na=5.34

acceleration is 5.34 m/s^2. The distance is multiplication of acceleration and square of the time.

x=1/2*a*t^2\n83.8=0.5*5.34*t^2\nt=5.6

After 5.6 second the wagon will ride 83.8 m up to hill. And the speed of wagon at that point is:

v=a*t\nv=29.9

What distinguishes mass from weight?A.
Mass is a measure of the amount of matter in an object, while weight is a measure of the force of gravity on the object.
B.
Weight is a measure of the amount of matter in an object, while mass is a measure of the force of gravity on the object.
C.
Mass is a measure of an object's inertial force, and weight is the force exerted by that object on other objects.
D.
Mass and weight are synonyms and ultimately describe the same principle.

Answers

Weight is a measurement of the object's gravitational pull, whereas mass is a measure of the amount of substance in the thing. The right answer is A.

What are mass and weight?

Mass is a measure of a physical body's entire makeup. This term also measures inertia, or the body's resistance to acceleration when a net force is applied. The basic mass unit of the SI is the kilogram.

The weight of an object refers to the gravitational force acting on it. Weight is the term used in many widely used textbooks to describe the gravitational force acting on the object. The mass is a matter present and the weight is the force.

Therefore, the weight is a measurement of the object's gravitational pull, whereas mass is a measure of the amount of substance in the thing. The right answer is A.

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Final answer:

Mass is the measure of how much matter an object has and remains constant regardless of location, while weight is the measure of the force of gravity acting on that object, which varies based on the gravitational environment.

Explanation:

Mass is a measure of the amount of matter in an object. It is a property that reflects how much space that object occupies in three-dimensional space. It remains constant regardless of where the object is.

On the other hand, weight is a measure of the force of gravity acting on the object. Weight can change based on the gravitational force of the environment; for example, an object weighs less on the moon than it does on Earth because the moon's gravitational force is less than Earth's.

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A pre-trip inspection will help you ____________.A. find problems that could cause a collision or breakdown
B. avoid a post-trip inspection
C. know how far you must travel
D. save money on fuel

Answers

Answer:

A. find problems that could cause a collision or breakdown

Explanation:

A pretrip inspection allows the driver to drive safely because he feels satisfied since he already had checked each and everything in the beginning. This increases the focus on driving. In addition to it there are less chances of happenings and technical faults in the vehicle. It also plays a vital role in the safety circumstances as well.

Answer
A.To find problems that could cause a collision or breakdown.

Explanation
A pre-trip inspection is the trip made by the organizers before the due date of the trip.
There are many reasons why pre-trip inspection is necessary. Some of them include:
1. Finding out how much information is available,
2. The cost to be incurred,
3. Assessing the route and the safety of the place,
4. The most important been to help in preparation of the budget and many others
From the choices given, the most appropriate answer is A. To find problems that could cause a collision or breakdown.

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Answers

Answer:

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Explanation:

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Answers

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Polychlorinated biphenyls (PCBs) have been banned because they are an environmental hazard. Which of the following was NOT a reason for banning them?

Answers

Answer:

PCBs have high electrical resistance and are excellent insulating materials.

Explanation:

Polychlorinated biphenyls [PCBs] are industrial chemical compounds made by man, which contains carbon, hydrogen and chlorine atoms. They can be used in the production of paints and dyes, heat transfer, etc.

There has been the ban on the use of these compounds because they are said to be very stable, and yield slowly to degradation by nature. They have low and not high electrical resistance.