MATHEMATICS MIDDLE SCHOOL

the isosceles triangle has two sides of equal length, a, that sre longer than the length of the base ,b. the equation 2a+b=15.7 can be used to find the sides length. if one of the longer sides is 6.3 centimeters what is the length of the base

Answers

Answer 1

Answer:

Answer:

base = 3.1 cm

Step-by-step explanation:

b= base

perimeter= p

From the statement we know that p=15.7 cm

moreover:

a=c=6.3 cm

So we have:

15.7=2*a +b

15.7 = 2*6.3 +b

15.7-12.6 = b

b= 3.1 cm = base

Therefore he took 40 gram of $1^(st)$ type solution and 10 gram of $2^(nd)$ type solution.

Step-by-step explanation:

Giventhat , A pharmacist 13% alcohol solution another 18% alcohol solution .

Let he took x gram solution of $1^(st)$ type solution

and he took (50-x) gram of $2^(nd)$ type solution.

Total amount of alcohol = $[x*(13)/(100)] +[(50 -x) *(18)/(100) ]$ gram

Total amount of solution = 50 gram

According to problem

⇔ $( [x*(13)/(100)] +[(50 -x) *(18)/(100) ])/(50)= (14)/(100)$

⇔ $(13x +900-18x)/(100*50) =(14)/(100)$

⇔- 5x= 700 - 900

⇔5x = 200

⇔x = 40 gram

Therefore he took 40 gram of $1^(st)$ type solution and (50 -40)gram = 10 gram of $2^(nd)$ type solution.

Answer:

40 of first and 10 of second

Step-by-step explanation:

What's 27 divided by 4 is

Answers

27 divided by 4 can be solved easily. 4 goes into 27 6 times because 4 times 6 is 24. You would be left with a remainder of 3.

Your answer would be 6 r 3

If you are looking for the decimal answer, then your answer would be 6.75.

Captain Jessica has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Luis and his merciless band of thieves. The Captain has probability 4/9 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability 1/4 .If both fire their cannons at the same time, what is the probability that both the pirate and the Captain hit each other's ships?

Answers

Answer: Probability that both the pirate and the Captain hit each other's ships is $(1)/(9)$

Step-by-step explanation:

since we have given that

Probability that the captain hits the pirate ship is given by

$(4)/(9)$

Probability that the pirate hits the Captains's ship is given by

$(1)/(4)$

So, we have to find the "Probability that both the pirate and the Captain hit each other's ship" is given by

$P(\text{Captain hits})* P(\text{ Pirates hit})\n\n=(4)/(9)* (1)/(4)\n\n=(1)/(9)$

Hence, probability that both the pirate and the Captain hit each other's ships is $(1)/(9)$

The probability that both the pirate and the Captain hit each other's ships is $(1)/(9)$ . This can be calculated by calculating the joint probability of both events.

What is joint probability?

A joint probability is a probability that two events will occur together and at the same time. Simply it is the probability that A occurs at the same time when B occurs. It can be calculated as:

$P(A and B) = P(A) * P(B)$ , where P(A and B) is the joint probability of A and B occurring together, P(A) is the probability of A, and P(B) is the probability of B.