Hi!
The answer would be three days a week
Bone-strengthening activity is key to ensuring that bones remain healthy to maintain an individual's lifestyle. The physical activity to strengthen bone may be brisk walking, exercises that include weights, or gymnastics to lift a few. The purpose of these activities are to observed to contribute to an increase in the bone mineral density of adolescents and children. Several studies have established that about 150 minutes a week for adults, or 3 days a week (60 minutes a day) for the youth should be devoted to bone strengthening physical activity to ensure good health of the body.
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Answer:
three or more days a week
Explanation:
Answer:
(a) 200.0628 N ; ( b) 4.08Kg
Explanation:
We know,
w = mg [here w= weight , m= mass , g= gravity]
now,
gravity on earth (g) =9.807 m/s²
mass of the spanner (m)=?
weight of the spanner on earth(w) = 40N
⇒ w = 40N
⇒m g =40N
⇒m = (40/g) Kg
⇒m= (40/9.807)Kg
∴m=4.08Kg
∴mass of the spanner on earth = 4.08Kg
We know,
Mass is the amount of matter in an object . Somass will remain same both on earth and jupiter.
So,
(b)The mass of the spanner on jupiter = 4.08Kg
Now,
The mass of the spanner on jupitar (m) = 4.08Kg
Gravity on jupiter (g*) = 5.g [5 times on earth]
= 5 . (9.807)m/s²
=49.035 m/s²
(a)
∴weight of the spanner on jupitar(w*) = m g*
=(4.08 x 49.035) N
=200.0628 N
(2) revolution of the Moon around Earth
(3) rotation of Earth on its axis
(4) rotation of the Moon on its axis
When water vapor condenses, how much heatenergy will be released into the atmosphere?
(1) 2260 joules/gram
(2) 4.18 joules/gram
(3) 334 joules/gram
(4) 2.11 joules/gram
Solution:
Step wise solution
Let r1 be the distance from the Earth to the point where
the gravitational accelerations are the same and let r2 be the distance
from the Moon to that point.
Then, r1+ r2 = r12 = 383,000 km.
Let Re be the radius of earth
and let Rm be the radius of moon
Let, ge be the gravity of earth
and let gm be the gravity of moon
The fact that the gravitational attractions by the Earth and the Moon
at this point are equal leads to the equation
gE(Re/r1)=gM(Rm/r2)
9.8(6380/r1)=1.62(1738/r12-r1)
(here, Re=6380, gE=9.8m/s^2, gM=1.62m/s^2 and r12=383,000 km
9.8*6380/(1.62*1738)=r1/(383000-r1)
therefore,
r1=344,770 km
Hope this answer wil help you
Answer:
Calculate the distance between the center of the earth and the center of the moon at which the gravitational force exerted by the earth on an object is equal in magnitude to the force exerted by the moon on the object
Explanation:
solution steps
Eliminate
B) they would not be able to see anything outside the window.
C) lasers can not be transmitted through the vacuum of space.
D) the sound of the explosion would not be transmitted back to their ship.