The ratio of new books to all books is 5:12.
In this scenario, there are 5 new books and 7 used books on a shelf. We will determine the ratio of new books to all books and explain it mathematically.
To find the ratio of new books to all books, we need to compare the number of new books to the total number of books, which includes both new and used books. In this case, there are 5 new books and 7 used books, so the total number of books is 5 + 7 = 12.
Now, let's define the ratio of new books to all books using the mathematical notation. We'll use "n" to represent the number of new books, "u" to represent the number of used books, and "t" to represent the total number of books.
Let:
n = 5 (number of new books)
u = 7 (number of used books)
t = n + u = 5 + 7 = 12 (total number of books)
The ratio of new books to all books is given by n/t. Substituting the values, we get:
Ratio of new books to all books = 5 / 12
The ratio can also be expressed in fractional form as 5/12. This means that out of every 12 books on the shelf, 5 are new books, and the remaining 7 are used books. The ratio is simplified to its lowest terms, making it a concise representation of the relationship between new books and all books on the shelf.
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a. b+2 (b+2b)
b. 3b+b
c. 2(2b)
Answer:
They are b and c.
Step-by-step explanation:
Let's simplify each expression:
a. b+2 (b+2b)
= b + 2b + 4b = 7b.
b. 3b + b = 4b.
c. 2(2b) = 2 * 2b = 4b.
Answer:
hello :
expressions are equivalent to 4b :
b ) 3b +b = 4b
c) 2(2b) = 4b
but : a) is not equivalent to 4b
because : b+2 (b+2b) = b + 2b +4b = 7b
16y3/20y4 (that's a y to the third power for sixteen and a y to the fourth power for twenty)
6xy/16y
Abc/10abc
Mn2/pm5n (that's an n to the second power for nm and a m to the fifth power on pmn)
12h3k/16h2k2 ( that's a h to the third power for 12hk and a h to the second power and k to the second power for 16hk
8x/10y
24n2/28n ( that's a n to the second power)
30hxy/54kxy
5jh/15jh3 (that's a h to the third power for 15jh)
20s2t3/16st5 ( that's a a to the second power and t to the third power for 20st and t to the fifth power for 16st)
Answer:
7π/6.
Step-by-step explanation:
The range in the third quadrant is π to 3π/2 ( or π to 1.5π) so its not π/3 or 3π/4.
5π/3 = 1.67π so it's not this one.
7π/6 = 1.167π so it's this one.