XY = -4
There are 5 large dogs and 3 small dogs
Let "S" be the number of small dogs
Let "L" be the number of large dogs
Given that There are a total of 8 small and large dogs
So we can frame a equation as:
number of small dogs + number of large dogs = 8
S + L = 8 ------- eqn 1
You realize there are 2 more large dogs than small dogs
Number of large dogs = 2 + number of small dogs
L = 2 + S -------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "L" and "S"
Substitute eqn 2 in eqn 1
S + 2 + S = 8
2S + 2 = 8
2S = 6
Substitute S = 3 in eqn 2
L = 2 + 3 = 5
Thus there are 5 large dogs and 3 small dogs
Answer:
5 large dogs and 3 small dogs
Step-by-step explanation:
The length of the edge of the given cube that has a lateral area of 36 square inches is: 3 inches.
Lateral area of a cube = 4a², wherea is the length of each edge of the cube.
Given the parameters:
4a² = 36
a² = 36/4
a² = 9
a = 3 inches.
Length of each edge of the cube = 3 inches.
Learn more about lateral area of cube on:
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