Why are plant cells and animal cells different

Answers

Answer 1
Answer: The Plant cell has cell walls to prevent it from basting in case of large amount of water.
while the animal cell doesn't have cell walls.
                 
                                  P.S. PHANTOM SNIPERS

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What volume of oxygen gas at 25 degrees celsius and 1.04 atm is needed for the complete combustion of 5.53g of propane

Answers

Answer: 14.7 L of oxygen gas at 25 degrees celsius and 1.04 atm is needed for the complete combustion of 5.53g of propane

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number 6.023* 10^(23) of particles.

\text{Number of moles of propane}=\frac{\text{Given mass}}{\text{Molar mass}}=(5.53g)/(44.1g/mol)=0.125moles

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

According to stoichiometry :

1 mole of propane requires 5 moles of oxygen  

Thus 0.125 moles of propane require=(5)/(1)* 0.125=0.625moles moles of oxygen  

According to the ideal gas equation:'

PV=nRT

P = Pressure of the gas = 1.04 atm

V= Volume of the gas = ?

T= Temperature of the gas = 25°C = 298 K  

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= 0.625

V=(nRT)/(P)=(0.625* 0.0821* 298)/(1.04)=14.7L

Final answer:

To find the volume of oxygen gas needed for the complete combustion of propane at given conditions, use stoichiometric calculations based on the balanced chemical equation and apply the ideal gas law.

Explanation:

The question is asking for the volume of oxygen gas required for the complete combustion of a given amount of propane at a specified temperature and pressure. To solve this, stoichiometry must be used along with the ideal gas law. The balanced chemical equation for the combustion of propane (C3H8) is:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l)

This equation indicates that one mole of propane reacts with five moles of oxygen. First, calculate the moles of propane by dividing the given mass of propane by its molar mass. Then, use the stoichiometric relationship from the balanced equation to find the moles of oxygen needed. Finally, apply the ideal gas law (PV=nRT) to calculate the required volume of oxygen at the given conditions (remembering to convert temperature to Kelvin and pressure to atm if necessary).

Learn more about Stoichiometry here:

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In the reaction, A → Products, the rate constant is 3.6 × 10−4 s−1. If the initial concentration of A is 0.548 M, what will be the concentration of A (in M) at t = 99.2 s? Only enter the numerical value with three significant figures in the answer box below. Do NOT type in the unit (M).

Answers

The value of the concentration of A is 0.529.

Since the rate constant has units of s⁻¹, we can tell that the order of the reaction is 1.

Rate of first -order reaction,

(A)=A_(0) e^(-kt)

Here, A_(0) is the initial concentration, t is the time, A is the final concentration, and k is the rate constant.

Substitute the given value values in the equation as follows,

(A)=0.548M e^{-3.6*10^{-4s^(-1)*99.2s } } \n=0.529M

The concentration of A in (M) is 0.529.

Find more information about first- order reaction here,

brainly.com/question/13309369

     

     

     

Answer:

        \large\boxed{\large\boxed{0.529M}}

Explanation:

Since the rate constant has units of s⁻¹, you can tell that the order of the reaction is 1.

Hence, the rate law is:

       r=d[A]/dt=-k[A]

Solving that differential equation yields to the well known equation for the rates of a first order chemical reaction:

      [A]=[A]_0e^(-kt)

You know [A]₀, k, and t, thus you can calculate [A].

       [A]=0.548M* e^{-3.6\cdot 10^(-4)/s*99.2s}

       [A]=0.529M

Which statement best relates an empirical formula with a molecular formula? They are always different for the same compound. Subscripts of empirical formulas can be reduced. Molecular formulas can be determined from empirical formulas. They both show the actual ratio of elements for a compound.

Answers

ANSWER

empirical formula is the simplest ratio of whole numbers of components making up a compound

molecular formula is the actual composition of components making up a compound

to analyse each statement

A.They are always different for the same compound. -

the empirical formula in some instances can be the same as the molecular formula. therefore this statement is incorrect.

B. Subscripts of empirical formulas can be reduced

empirical formula gives the simplest ratios and the subscripts cannnot be further simplified therefore this is incorrect

C. Molecular formulas can be determined from empirical formulas

using the empirical formula, the molecular formula can be determined. therefore its correct.

D. They both show the actual ratio of elements for a compound

only the molecular formula gives the actual ratio of elements whereas the empirical formula gives the simplest ratio of elements. this statement is incorrect

The correct statement is C.

Answer:

Molecular formulas can be determined from empirical formulas.

Explanation:

What volume is equivalent to 12.0 m3?

Answers

i think 12000 is the answer

During a chemical reaction can only 1 substance be produced? Why or why not

Answers

The chemical reaction produces a new substance with new and different physical and chemical properties. Matter is never destroyed or created in chemical reactions. The particles of one substance are rearranged to form a new substance. .

a ball is rolling across the floor.How could you apply an unbalanced force to change the speed or direction of the ball?

Answers

Usually a ball would roll toward the side that's lower, so if you had a ramp and put it on the side that was lower, then the ball would change direction and go the opposite direction


Kick the ball! The force of the kick likely isn't the same amount of force acting on the ball as it's rolling, so as long as the kick makes the ball go faster (or slower) than it had been, that force is unbalanced