Answer: 14.7 L of oxygen gas at 25 degrees celsius and 1.04 atm is needed for the complete combustion of 5.53g of propane
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number of particles.
According to stoichiometry :
1 mole of propane requires 5 moles of oxygen
Thus 0.125 moles of propane require= moles of oxygen
According to the ideal gas equation:'
P = Pressure of the gas = 1.04 atm
V= Volume of the gas = ?
T= Temperature of the gas = 25°C = 298 K
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas= 0.625
To find the volume of oxygen gas needed for the complete combustion of propane at given conditions, use stoichiometric calculations based on the balanced chemical equation and apply the ideal gas law.
The question is asking for the volume of oxygen gas required for the complete combustion of a given amount of propane at a specified temperature and pressure. To solve this, stoichiometry must be used along with the ideal gas law. The balanced chemical equation for the combustion of propane (C3H8) is:
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l)
This equation indicates that one mole of propane reacts with five moles of oxygen. First, calculate the moles of propane by dividing the given mass of propane by its molar mass. Then, use the stoichiometric relationship from the balanced equation to find the moles of oxygen needed. Finally, apply the ideal gas law (PV=nRT) to calculate the required volume of oxygen at the given conditions (remembering to convert temperature to Kelvin and pressure to atm if necessary).
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The value of the concentration of A is 0.529.
Since the rate constant has units of s⁻¹, we can tell that the order of the reaction is 1.
Here, is the initial concentration, t is the time, A is the final concentration, and k is the rate constant.
Substitute the given value values in the equation as follows,
The concentration of A in (M) is 0.529.
Find more information about first- order reaction here,
Answer:
Explanation:
Since the rate constant has units of s⁻¹, you can tell that the order of the reaction is 1.
Hence, the rate law is:
Solving that differential equation yields to the well known equation for the rates of a first order chemical reaction:
You know [A]₀, k, and t, thus you can calculate [A].
ANSWER
empirical formula is the simplest ratio of whole numbers of components making up a compound
molecular formula is the actual composition of components making up a compound
to analyse each statement
A.They are always different for the same compound. -
the empirical formula in some instances can be the same as the molecular formula. therefore this statement is incorrect.
B. Subscripts of empirical formulas can be reduced
empirical formula gives the simplest ratios and the subscripts cannnot be further simplified therefore this is incorrect
C. Molecular formulas can be determined from empirical formulas
using the empirical formula, the molecular formula can be determined. therefore its correct.
D. They both show the actual ratio of elements for a compound
only the molecular formula gives the actual ratio of elements whereas the empirical formula gives the simplest ratio of elements. this statement is incorrect
The correct statement is C.
Answer:
Molecular formulas can be determined from empirical formulas.
Explanation:
i think 12000 is the answer
The chemical reaction produces a new substance with new and different physical and chemical properties. Matter is never destroyed or created in chemical reactions. The particles of one substance are rearranged to form a new substance. .
Usually a ball would roll toward the side that's lower, so if you had a ramp and put it on the side that was lower, then the ball would change direction and go the opposite direction