2
−
3
+
6
d
2
c
−3+
d
6
start fraction, c, divided by, 2, end fraction, minus, 3, plus, start fraction, 6, divided by, d, end fraction when
c
=
14
c=14c, equals, 14 and
d
=
3
Answer:
The answer = 6
Step-by-step explanation:
Given expression:
To evaluate the given expression, when and
Solution:
We have:
Plugging in and in the given expression, to evaluate.
⇒
Evaluating:
⇒
⇒ 6(Answer)
Answer:
hmm 6
Step-by-step explanation:
Answer:
The enthalpy change per mole of sodium when sodium reacts with water is 28.36 kJ
Step-by-step explanation:
The given parameters are;
Mass of sodium = 8 grams = 0.008 kg
Volume of water = 227 cm³ = 0.000227 m³
Initial water temperature, T₁ = 298 K
Final water temperature, T₂ = 308.4 K
Specific heat capacity of water = 4.18 J/(K·g)
Density of water = 1000 kg/m³
Mass of water = 1000×0.000227 = 0.227 kg = 227 g
Heat change, ΔH = m×c×ΔT = m×c×(T₂ - T₁)
ΔH = 227*4.18*(308.4 - 298) = 9868.144 J = 9.868 kJ
Molar mass of sodium = 22.989769 g/mol
Therefore, 8 grams contains;
8/22.989769 = 0.348 moles of Na
Which gives the enthalpy change per 0.348 moles of Na when sodium reacts with water = 9.868 kJ
Therefore, when one mole of Na reacts with water we have;
The enthalpy change per 0.348/0.348 = 1 mole of Na when sodium reacts with water = 9.868 kJ/0.348 = 28,358.3 J = 28.36 kJ.
Answer:
Peggy completed more of the math homework than Al
Step-by-step explanation:
we have
Peggy completed of the math homework
Al completed of the math homework
we know that
In order to be able to compare fractions more easily it is recommended that both have the same denominator
so
Multiply by
Multiply by
therefore
Peggy completed more of the math homework than Al
B) -3 units
C) 3 units
D) 21 units